Answer:
The other signal that would indicate the presence of a C= C bond appears close to 3100
.
Explanation:
Bands that appear above 3000
are often unsaturation diagnoses suggest. The band at 3000-
3100
is characteristics for C-H stretching frequencies and normally is overlaps with the ones for alkanes because it is a band of weak intensity.
Answer: acetone molecule ( CH₃-CO-CH₃)
Explanation:
1) Acetone is CH₃-CO-CH₃
2) That is a molecule (build up of covalent bonds).
3) When dissolved, covalent bonded compounds remain as separate molecules, then it is said that the major species present in the solution is the molecule. The molecules of acetone are surrounded (sovated) by the molecules of water.
This as opposed to the case of ionic compounds that ionize. When a compound as NaCl dissolves in water, it ionizes completely, so the major speceies are not NaCl formulas, but the ions Na⁺ and Cl⁻, not molecules.
That leads to the answer: the major species present when acetone is dissolved in water is the molecules of acetone (you do not need to state the fact that the molecules of water are part of the solution, because that is not the target of the question).
Answer:
The possible structures are ketone and aldehyde.
Explanation:
Number of double bonds of the given compound is calculated using the below formula.

=Number of double bonds
= Number of carbon atoms
= Number of hydrogen atoms
= Number of nitrogen atoms
The number of double bonds in the given formula - 

The number of double bonds in the compound is one.
Therefore, probable structures is as follows.
(In attachment)
The structures I and III are ruled out from the probable structures because the signal in 13C-NMR appears at greater than 160 ppm.
alkene compounds I and II shows signal less than 140 ppm.
Hence, the probable structures III and IV are given as follows.
The carbonyl of structure I appear at 202 and ketone group of IV appears at 208 in 13C, which are greater than 160.
Hence, the molecular formula of the compound
having possible structure in which the signal appears at greater than 160 ppm are shown aw follows.
The net cell reaction for the iron-silver voltaic cell would be:
<span>3Ag+ + Fe --------> 3Ag + Fe3+
</span>
wherein it comes from the reaction of the cathode and the anode:
<span>Ag+ + e- -------> Ag, for the cathode and;
</span>
<span>Fe -------> Fe3+ + 3e-, for the anode
</span>
When both equations would be multiplied, the it would now yield the balanced net reaction as stated above.