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jok3333 [9.3K]
2 years ago
12

Describe the "clock" direction of surface currents in the northern hemisphere. 2. describe the "clock" direction of surface curr

ents in the southern hemisphere. 3. what is the most common source of energy for surface currents? 4. what is the relationship between the movement of the atmosphere and the movement of surface currents?
Physics
1 answer:
dem82 [27]2 years ago
8 0
- The currents flow in certain patterns through the world.

- The currents in the northern hemisphere flow clockwise up from the equator toward the polar regions and then back.

- While the currents in the southern hemisphere flow in a counterclockwise direction south from the equator to the polar regions.

- Surface water cooled in the polar region. Near the poles, the surface water is cooled and becomes heavier. This cool, heavy water sinks and flows towards the equator. Along the way, it mixes with warmer, fresh water and gradually rises. eventually, the surface waters are moved by the winds toward the polar regions to complete the cycle. 

- The surface current is driven by wind and follow global atmospheric patterns. Cold surface currents move from the polar regions to the equatorial zones, and warm surface current moves in opposite way.
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Answer:

the final temperature of the gas is 785.18 K

Explanation:

The computation of the final temperature of the gas is shown below:

Here we apply the gas law

= PV ÷ T

Given that

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V1 = 24.6 L

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Now

P1V1 ÷ T1 = P2V2 ÷ T2

(1.9 × 24.6) ÷ 335 = (3.5 × 31.3)/T2

T2 = 785.18 K

hence, the final temperature of the gas is 785.18 K

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2 years ago
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A uniform magnetic field of 0.50 T is directed along the positive x axis. A proton moving with a speed of 60 km s enters this fi
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Explanation:

It is given that,

Magnetic field, B = 0.5 T

Speed of the proton, v = 60 km/s = 60000 m/s

The helical path followed by the proton shown has a pitch of 5.0 mm, p = 0.005 m

We need to find the  angle between the magnetic field and the velocity of the proton. The pitch of the helix is the product of parallel component of velocity and time period. Mathematically, it is given by :

p=v_{||}\times T

p=v\ cos\theta\times \dfrac{2\pi m}{Bq}

cos\theta=\dfrac{pBq}{2\pi mv}

cos\theta=\dfrac{0.005\times 0.5\times 1.6\times 10^{-19}}{2\pi \times 1.67\times 10^{-27}\times 60000}

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So, the angle between the magnetic field and the velocity of the proton is 50.58 degrees. Hence, this is the required solution.

3 0
2 years ago
A student decides to spend spring break by driving 50 miles due east, then 50 miles 30 degrees south of east, then 50 miles 30 d
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Explanation: The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.

The sum of exterior angles of a polygon = 360 degrees.

Exterior angle of a polygon = (360 ÷ number of sides)

Therefore,

Number of sides = 360 ÷ exterior angle

Exterior angle = 30 degrees

Hence,

Number of sides = 360 ÷ 30 = 12 sides

Since distance traveled of 50 miles is the same for each displacement ;

Total displacement = distance traveled * number of sides

Total displacement = 50 * 12 = 600 miles.

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D

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