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Misha Larkins [42]

2 years ago

14

A 70 kilogram mountaineer is standing on the summit of Mt. Everest. The distance between the mountaineer and the center of Earth

is 6.39 × 106 meters. What is the magnitude of the force of gravity acting on the mountaineer? (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)

2 answers:

Vilka [71]2 years ago

5 0

F = GMm/r²
F = (6.673*10^-11)(5.98*10^24)(70)/(6.39*10^...
F = 684 N (3sf)

Korvikt [17]2 years ago

5 0

Answer: The magnitude of the force of gravity acting on the mountaineer 684.09 Newtons.

Explanation:

Mass of the earth , M = $5.98\times 10^{24] kg$

Mass of the mountaineer, m = 70 kg

Distance between mountaineer and Earth,r : $6.39\times 10^{6} m$

Gravitational constant ,G = $6.673\times 10^{-11} N m^2/kg^2$

$F=G\frac{Mm}{r^2}=6.673\times 10^{-11} N m^2/kg^2\frac{5.98\times 10^{24} kg\times 70 kg}{(6.39\times 10^{6} m)^2}$

$F=684.09 N$

The magnitude of the force of gravity acting on the mountaineer 684.09 Newtons.

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What resistance must be connected in parallel with a 633-Ω resistor to produce an equivalent resistance of 205 Ω?

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Answer:

303 Ω

Explanation:

Given

Represent the resistors with R1, R2 and RT

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Required

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Since it's a parallel connection, it can be solved using.

1/Rt = 1/R1 + 1/R2

Substitute values for R1 and RT

1/205 = 1/633 + 1/R2

Collect Like Terms

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The formula for the horizontal range of the projectile is given by

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The maximum value of Sin2θ is 1.

It means 2θ = 90

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Thus, the range is maximum when the angle of projection is 45 degree.

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The energy stored in a wooden log transforms when the log is burned. Which of the following explanations BEST describes how the

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Answer:

The options are approximations of the exact answers:

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A) The electric field in a parallel plate capacitor is given by the formula $E=\frac{\sigma}{k\epsilon_0}$ , where $\epsilon_0=8.85\times10^{-12}C/Vm$ and in our case $\sigma=10^5C/m^2$ and, for air, $k=1.00059$ , so we have:

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B) The K+ ion has one elemental charge excess, so its charge is $q=1.6\times10^{-19}C$ , and the force a charge experiments under an electric field E is given by F=qE, so we have:

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$K=(3\times10^{-15}C)(1.13\times10^{-2}V)=3.39\times10^{-17}J$

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