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Rasek [7]
2 years ago
11

If 10.0 liters of H2(g) at stp is heated to a temperature of 546 K what is the new volume

Chemistry
1 answer:
Damm [24]2 years ago
8 0
Answer is: new volume is 19,99 L.
V₁(H₂) = 10,0 L.
T₁(H₂) = 0°C = 273,15 K.
T₂(H₂) = 546 K.
V₂(H₂) = ?
Charles' Law:  The Temperature-Volume Law - <span>the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:
V</span>₁/T₁ = V₂/T₂.
<span>10,0 L/273,15 K = V</span>₂/546 K.
<span>V</span>₂ = 19,99 L.<span>
</span>
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