If 10.0 liters of H2(g) at stp is heated to a temperature of 546 K what is the new volume

1 answer:

8 0

Answer is: new volume is 19,99 L.
V₁(H₂) = 10,0 L.
T₁(H₂) = 0°C = 273,15 K.
T₂(H₂) = 546 K.
V₂(H₂) = ?
Charles' Law: The Temperature-Volume Law - the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:
V₁/T₁ = V₂/T₂.
10,0 L/273,15 K = V₂/546 K.
V₂ = 19,99 L.

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