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VMariaS [17]
1 year ago
9

The largest salami in the world, made in Norway, was more than 20 m long. If a hungry mouse ran around the salami’s circumferenc

e with a tangential speed of 0.17 m/s, the centripetal acceleration of the mouse was 0.29 m/s2 . What was the radius of the salami?
Physics
1 answer:
Musya8 [376]1 year ago
8 0

Answer: 0.09 m

Explanation:

Centripetal acceleration in terms of tangential speed is:

a_c=\frac{v^2_t}{r}

where r is the radius.

It is given that,

centripetal acceleration of the mouse, a_c=0.29 m/s^2

tangential speed , v_t=0.17m/s

Radius of salami is:

r =\frac{(0.17m/s)^2}{0.29 m/s^2}=0.09m

Thus, the radius of the salami is 0.09 m.

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If the blocks are released from rest, which way does the 10 kg block slide, and what is its acceleration? enter a positive value
anyanavicka [17]
<span>Let m1=10kg and m2=5kg and for our calculations assume right is positive and up is positive (note: for block hanging, the x axis is vertical so tilt your head to help) For m1 Sigma Fx = ma T - m1gsin35 = m1a where T = tension For m2 m2g - T = m2a Add equation together m1a + m2a = T-m1gsin35 + m2g - T a(m1 + m2) = m2g - m1gsin35 a= (5*9.8 - 10*9.8*sin35)/(10 + 5) a= -0.48m/s/s So the system is moving in the opposite direction of our set coordinate system where we said right positive, its negative so its moving left therefore down the ramp</span>
6 0
2 years ago
Read 2 more answers
The voltage across the terminals of a 9.0 v battery is 8.5 v when the battery is connected to a 60 ω load. part a what is the ba
snow_lady [41]
Refer to the diagram shown below.

i = the current in the circuit., A
R₁ = the internal resistance of the battery, Ω
R₂ = the resistance of the 60 W load, Ω

Because the resistance across the battery is 8.5 V instead of 9.0 V, therefore
(R₁ )(i A) = 9 - 8.5 = (0.5 V)
R₁*i = 0.5         (10

Also,
R₂*i = 9.5         (2)

Because the power dissipated by R₂ is 60 W, therefore
i²R₂ = 60
From (2), obtain
i*9.5 = 60
i = 6.3158 A

From (1), obtain
6.3158*R₁ = 0.5
R₁ = 0.5/6.3158 = 0.0792 Ω = 0.08 Ω (nearest hundredth)

Answer: 0.08 Ω

3 0
1 year ago
Read 2 more answers
Max and Jimmy want to jump on a trampoline. Max begins jumping in a steady pattern, making small waves in the trampoline. Jimmy
mylen [45]

Answer:

x_total = (A + B) cos (wt + Ф)

we have the sum of the two waves in a phase movement

Explanation:

In this case we can see that the first boy Max when he enters the trampoline and jumps creates a harmonic movement, with a given frequency. When the second boy Jimmy enters the trampoline and begins to jump he also creates a harmonic movement. If the frequency of the two movements is the same and they are in phase we have a resonant process, where the amplitude of the movement increases significantly.

         Max

               x₁ = A cos (wt + Ф)

         Jimmy

              x₂ = B cos (wt + Ф)

         

total movement

             x_total = (A + B) cos (wt + Ф)

 Therefore we have the sum of the two waves in a phase movement

8 0
1 year ago
If one replaces the conducting cube with one that has positive charge carriers, in what direction does the induced electric fiel
Grace [21]

Answer:

There will be no change in the direction of the electric field .

Explanation:

The direction will remain the same because the sign of the charges has no effect on it.

When one replaces the conducting cube with one that has positive charge carriers there will be no change in the direction of the field as there is no defined relationship between the direction of the electric field and sign of the charge.

3 0
2 years ago
A stone falls from rest from the top of a cliff. A second stone is thrown downward from the same height 2.7 s later with an init
Darina [25.2K]

Answer:4.05 s

Explanation:

Given

First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s

Both hit the ground at the same time

Let h be the height of cliff and it reaches after time t

h=\frac{gt^2}{2}

For second stone

h=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}---2

Equating 1 &2 we get

\frac{gt^2}{2}=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}

\frac{g}{2}\left ( t-t+2.7\right )\left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0

13.23\times \left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0

26.46t-35.721-52.92t+142.884=0

t=4.05 s

4 0
2 years ago
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