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butalik [34]
2 years ago
9

On its own, a certain tow-truck has a maximum acceleration of 3.0 m/s2. what would be the maximum acceleration when this truck w

as towing a bus of twice its own mass?

Physics
2 answers:
vitfil [10]2 years ago
8 0

The maximum acceleration would be 1.0 m/s² when this truck was towing a bus of twice its own mass

\texttt{ }

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

initial acceleration = a₁ = 3.0 m/s²

mass of tow-truck = m₁ = m

mass of bus = m₂ = 2m

<u>Asked:</u>

final acceleration = a₂ = ?

<u>Solution:</u>

\texttt{Initial Force of Tow-Truck = Final Force of Tow-Truck }

F_1 = F_2

m_1 a_1 = m_2 a_2

m (3.0) = (m + 2m) a_2

3m = 3m (a_2)

a_2 = 3m \div 3m

\boxed{a_2 = 1.0 ~ \mathtt{ m/s^2}}

\texttt{ }

<h3>Conclusion :</h3>

The maximum acceleration would be 1.0 m/s²

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

olganol [36]2 years ago
5 0
Let's call a_1=3 m/s^2 the maximum acceleration of the truck alone. The force produced by the engine to accelerate the truck in this situation is
F= ma_1
with m being the mass of the truck alone.

If we attach a bus of twice the mass of the truck, now the whole system (truck+bus) has a mass of (m+2m)=3m. And in this case, the force produced by the engine is
F=3m a_2
with a2 being the new acceleration. 
The engine is always the same, so the force produced is still the same, so we can equalize F written in the first equation and in the second equation:
m a_1 = 3 m a_2
and find a2, the new acceleration:
a_2 =  \frac{m a_1}{3 m}=  \frac{a_1}{3}= \frac{3 m/s^2}{3}=1 m/s^2
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