1) The answer is: mass of water is 1.35 grams.
Balanced chemical reaction: 2H₂ + O₂ → 2H₂O.
m(O₂) = 1.2 g; mass of oxygen.
M(O₂) = 2 · 16 g/mol.
M = 32 g/mol, molar mass of oxygen.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 1.2 g ÷ 32 g/mol.
n(O₂) = 0.0375 mol; amount of oxygen, limiting reactant.
m(H₂) = 9.5 g; mass of hydrogen.
M(H₂) = 2 g/mol, molar mass of hydrogen.
n(H₂) = m(H₂) ÷ M(H₂).
n(H₂) = 9.5 g ÷ 2 g/mol.
n(H₂) = 4.5 mol; amount of hydrogen.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 0.0375 mol · 2.
n(H₂O) = 0.075 mol; amount of water.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 0.075 mol · 18 g/mol.
m(H₂O) = 1.35 g; mass of water.
2) The answer is: 3.05 grams of MgCl₂ is produced, the limiting reactant is Mg(OH)₂.
Balanced chemical reaction: 2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O.
m(Mg(OH)₂) = 1.85 g; mass of magnesium hydroxide
n(Mg(OH)₂) = m(Mg(OH)₂) ÷ M(Mg(OH)₂).
n(Mg(OH)₂) = 1.85 g ÷ 58.32 g/mol.
n(Mg(OH)₂) = 0.032 mol; limiting reactant.
m(HCl) = 3.71 g; mass of hydrochloric acid.
n(HCl) = 3.71 g ÷ 36.46 g/mol.
n(HCl) = 0.102 mol; amount of hydrochloric acid.
From chemical reaction: n(Mg(OH)₂) : n(MgCl₂) = 1 : 1.
n(MgCl₂) =0.032 mol; amount of magnesium chloride.
m(MgCl₂) = n(MgCl₂) · M(MgCl₂).
m(MgCl₂) = 0.032 mol · 95.21 g/mol.
m(MgCl₂) = 3.05 g; mass of magnesium chloride.
3) The answer is: mass of potassium hydroxide is 8.1 grams.
Balanced chemical reaction: K₂O + H₂O → 2KOH.
m(K₂O) = 8.2 g; mass of potassium oxide.
n(K₂O) = m(K₂O) ÷ M(K₂O).
n(K₂O) = 8.2 g ÷ 94.2 g/mol.
n(K₂O) = 0.087 mol; amount of potassium oxide.
m(H₂O) = 1.3 g; mass of water.
n(H₂O) = 1.3 g ÷ 18 g/mol.
n(H₂O) = 0.072 mol; limiting reactant.
From chemical reaction: n(H₂O) : n(KOH) = 1 : 2.
n(KOH) = 2 · 0.072 mol.
n(KOH) = 0.144 mol.
m(KOH) = 0.144 mol · 56.1 g/mol.
m(KOH) = 8.1 g; mass of potassium hydroxide.
4) The answer is: mass of aluminum chloride is 16.66 grams.
Balanced chemical reaction: 2Al + 3Cl₂ → 2AlCl₃.
m(Al) = 8.1 g; mass of aluminium.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 8.1 g ÷ 27 g/mol.
n(Al) = 0.3 mol.
V(Cl₂) = 4.2 L; volume of chlorine.
n(Cl₂) = 4.2 L ÷ 22.4 L/mol.
n(Cl₂) = 0.1875 mol; limiting reactant.
From chemical reaction: n(Cl₂) : n(AlCl₃) = 3 : 2.
n(AlCl₃) = 2 · 0.1875 mol ÷ 3.
n(AlCl₃) = 0.125 mol; amount of aluminium chloride.
m(AlCl₃) = 0.125 mol · 133.34 g/mol.
m(AlCl₃) = 16.66 g; mass of aluminium chloride.
