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Lunna [17]
2 years ago
3

Photons of light with an energy of 656 nm are being directed through a chamber of hydrogen gas atoms. the gas atoms began in the

ir ground state (ni=1). what happens?
Physics
2 answers:
viktelen [127]2 years ago
6 0

The hydrogen gas atoms would absorb the photon of energy 656nm, and electrons would get excited and move to a higher energy level. The energy level that the electron would occupy is given by the Rydberg formula

\frac{1}{ \lambda} = RZ^2 \times (\frac{1}{n_1^2} -\frac{1}{n_2^2}), where \lambda is wavelength of photon, 656nm, R is Rydberg constant 1.0973 \times 10^7m^-^1 , Z is atomic number of hydrogen 1.00794 u and n_1 and n_2 are the quantum numbers. So for the absorbed wavelength the new energy level is

\frac{1}{\lambda} = RZ^2 \times (\frac{1}{n_1^2 }-\frac{1}{1^2} )\\\\\frac{1}{\lambda} = RZ^2 \times( \frac{1}{n_1^2}- 1)\\n_1^2= 1 + \lambda RZ^2\\n_1^2= 1 + 656nm \times \frac{1 \times 10^-9m}{nm} \times 1.0973 \times 10^7 \times (1.008)^2 = 7.311\\n_1= \sqrt{7.311} \\n_1= 2.7,

This means n_1=3. So the hydrogen atom moves from n=1 to n=3 energy level.


ankoles [38]2 years ago
6 0

Since there is not quite enough energy for transition from n=1 to n=2. So, the photons will pass through the gas chamber without affecting the gas.

Further explanation:

If the energy of photons is enough to excite all the electrons to go in higher state, the electron absorbs the energy of photon and go from a lower energy state to higher energy state. Transition of electron from lower energy state t higher energy state depends on the energy of photons.

Given:

The wavelength of the photons directed through a chamber of hydrogen gas atoms is 656\text{ nm}.

The electron is excited from the energy state n=1 to higher energy state.

Concept:

The energy associated with a photon is given by the following relation.

E = \dfrac{{hc}}{\lambda}

Here, E is the energy associated with photon, h is the plank constant, c is the speed of the light and \lambda is the wavelength associated with photon.

Substitute 6.625\times{10^{-34}}\text{ J}\cdot\text{s} for h, 3.00\times{10^8}\text{ m/s}} for c and 656\text{ nm} for \lambda in the above expression.

\begin{aligned}E&=\frac{{\left( {6.625 \times {{10}^{ - 34}}\,{\text{Js}}} \right)\left( {3.0 \times {{10}^8}\,{\text{m/s}}} \right)}}{{\left( {656 \times {{10}^{ - 9}}\,{\text{m}}} \right)}}\\&=3.0281 \times {10^{-19}}\,{\text{J}}\\\end{aligned}

Rydberg equations is used to find out the energy level of an electron while transition from one energy state to another energy state.

\dfrac{1}{\lambda}=R{z^2}\left({\dfrac{1}{{n_1^2}}-\dfrac{1}{{n_2^2}}}\right)

Here, \lambda  is the wavelength of the photons directed through a chamber, R is the Rydberg constant, z is the atomic number of hydrogen atom, {n_1} is the lower energy state and {n_2} is the higher energy state.

Substitute 656\times{10^{-9}}\,{\text{m}} for \lambda, 1.0973 \times {10^7}\,{{\text{m}}^{{\text{-1}}}} for R, 1 for z and 1 for {n_1} in the above expression.

\dfrac{1}{{\left( {656 \times {{10}^{ - 9}}\,{\text{m}}} \right)}} = \left( {1.0973 \times {{10}^7}{\mkern 1mu} {{\text{m}}^{{\text{-1}}}}} \right){\left( 1 \right)^2}\left( {\dfrac{1}{{{{\left( 1 \right)}^2}}}-\dfrac{1}{{n_2^2}}}\right)

Simplify the above expression for {n_2}

\begin{aligned}{n_2}&=\sqrt{\dfrac{1}{{0.861}}}\\&=1.08\\\end{aligned}

From the above result it can be concluded that photons with wavelength 656\text{ nm} does not have enough energy to cause an electron to jump even one level higher.

Thus, there is not quite enough energy for transition from n=1 to n=2. So, the photons will pass through the gas chamber without affecting the gas.

Learn more:

1.  A Na+ ion moves from inside a cell brainly.com/question/9251988

2.  The kinetic energy of the emitted electrons when cesium is exposed to UV rays brainly.com/question/9059731

3. The frequency of the light for wavelength 7.1x10^2 nm brainly.com/question/9559140

Answer Details:

Grade: College

Subject: Physics

Chapter: Modern physics

Keywords:

Photons, light, energy, 656 nm, 656 times 10^-9 m, 6.56 times 10^-7 m, directed, chamber, hydrogen, gas atom, ground state, ni=1, 1.071, few, absorbed, quite enough, electrons, nf=2.

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