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Anton [14]
2 years ago
8

Find p(t, the x component of the total momentum of the system at time t. express your answer in terms of m1, m2, v1(t, and v2(t.

Physics
1 answer:
denpristay [2]2 years ago
6 0

The X-component of the momentum of the system is \boxed{{p_x}={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)} .

Further Explanation:

The momentum of a body is the amount of motion contained by the body. The momentum of a body is expressed as the product of the mass and velocity of the body at the particular instant.

The momentum of the body is represented as:

\boxed{p=m\times v}

For a system of particles, the momentum of the whole system is the vector sum of individual momentum of all the particles.

{\vec p_{net}}={\vec p_1}+{\vec p_2}+{\vec p_3}.....

Here, {\vec p_{net}}  is the net momentum of the system.

In the given question, both the particles are moving in the same direction i.e. X-direction. Therefore, the net momentum of the system in X-direction is the sum of the two momentum.

The velocity of the first particle at time t  is {v_1}\left(t\right) .

The momentum of the first particle is:

{p_1}={m_1}{v_1}\left(t\right)

The velocity of the second particle at time t  is {v_2}\left(t\right) .

The momentum of the second particle is:

{p_2}={m_2}{v_2}\left(t\right)

The X-component of the net momentum of the system is:

\begin{aligned}{p_x}&={p_1}+{p_2}\\&={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)\\\end{aligned}

Thus, the X-component of the momentum of the system is \boxed{{p_x}={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)} .

Learn More:

1. You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves down a frictionless track <u>brainly.com/question/10177389 </u>

2. A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4.5 m/s <u>brainly.com/question/9484203 </u>

3. A 50-kg meteorite moving at 1000 m/s strikes earth. Assume the velocity is along the line joining earth's center <u>brainly.com/question/6536722 </u>

Answer Details:

Grade: High School

Subject: Physics

Chapter: Force and Momentum

Keywords:

Momentum, X-component, total momentum, isolated system, velocity of the particle, v1(t), v2(t), composed of two blocks, masses m1 and m2.

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The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.
Reika [66]

Answer:

tan \theta = \mu_s

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

mg sin \theta - \mu_s R =0 (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, \theta the angle of the slope

\mu_s R is the frictional force, with \mu_s being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

R-mg cos \theta = 0

where

R is the normal reaction

mg cos \theta is the component of the weight perpendicular to the slope

Solving for R,

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_s mg cos \theta = 0

Re-arranging the equation,

sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of \mu_s, the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

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2 years ago
Suppose we were to attempt to use a similar machine to measure the charge-to-mass ratio of protons, instead. Suppose, for simpli
Igoryamba

Answer:

In summary, the biggest difference in the experiment is that the proton mass is much more than the electron mass, so the voltages used are high and very dangerous.

Explanation:

The machine to measure the ratio of charge / mass of the electron, has two parts: a part where it accelerates the electrons in an electric field and a second section to charter the beam and measure its radius of curvature calculated from here the q / m ratio

In the case of having protons, the charge has the same value as that of the electrons, but with a positive charge, so the polarities of the fields should be changed.

The mass of the protons is much greater than the mass of the electrons, which introduced a significant difference in the excrement, since similar electric fields the speed of the protons is much less than the speed of the electrons, so the magnetic field through which the voters pass to have equivalent deflations in many cases this small values ​​of the magnetic field are not desirable due to the interference of the Earth's magnetic field.

Another solution could be to increase the electric field to have the protons with speeds similar to the electors, this possibility is not easy either, because the field of trunking of more than 5000 V would be needed, which are very dangerous.

In summary, the biggest difference in the experiment is that the proton mass is much more than the electron mass, so the voltages used are high and very dangerous.

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A man pushes his child in a grocery cart. The total mass of the cart and child is 30.0 kg. If the force resisting the carts moti
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The force applied by the man is 60 N

Explanation:

We can solve this problem by applying Newton's second law, which states that:

\sum F = ma (1)

where

\sum F is the net force acting on the child+cart

m is the mass of the child+cart system

a is their acceleration

In this problem, we have:

m = 30.0 kg is the mass

a=1.50 m/s^2

And there are two forces acting on the child+cart system:

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  • The force resisting the cart motion, R = 15.0 N

Therefore we can write the net force as

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where R is negative since its direction is opposite to the motion

So eq.(1) can be rewritten as

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And solving for F,

F=ma+R=(30.0)(1.50)+15.0=60 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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Answer:

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