Since these are alternate interior angles, they should be congruent. Equating the measures given:
-x - 30 = 5x - 30
x = 0
However, this is not true, since the diagram clearly shows that there is a positive angle between them.
The best answer is choice B.
Let
x--------> the amount in dollars that Luis make last week
we know that

------> equation that represent the situation
solve for x
Divide by
both sides



therefore
<u>the answer is</u>

Answer:
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that the selection of the random pages will contain at least two errors is 0.2644
Step-by-step explanation:
From the information given:
Let q represent the no of typographical errors.
Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let
be the random variable that follows a Poisson distribution, then mean 
and the mean that the random selection of 50 pages will contain no error is 
∴

Pr(q =0) = 0.368
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that 50 randomly page contains at least 2 errors is computed as follows:
P(X ≥ 2) = 1 - P( X < 2)
P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2
![P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B%20%5Cdfrac%7Be%5E%7B-1%7D%201%5E0%7D%7B0%21%7D%20%2B%5Cdfrac%7Be%5E%7B-1%7D%201%5E1%7D%7B1%21%7D%20%5D)
![P(X \geq 2) = 1 - [0.3678 +0.3678]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B0.3678%20%2B0.3678%5D)

P(X ≥ 2) = 0.2644
The probability that the selection of the random pages will contain at least two errors is 0.2644
They are both correct in their computation
(28.5-28.5(.3))+.1(28.5-28.5(.3))=$21.945
28.5(.7)(1.1)=$21.945
And since they each have $22 to spend, they have enough to purchase the book.
Answer:
y = 0
Step-by-step explanation:
Since there is no indication of a shift in the graph of f(x) = 3cos(-0.25x), then the midline must be the normal midline for a cosine or sine function which is: y = 0.