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2 years ago

3

Bill's Hardware marks up snow blowers $130 and sells them for $485. Markup is on cost. What are the cost and percent markup to t

he nearest hundredth percent?

1 answer:

Nady [450]2 years ago

7 0

The cost is $485 -130 = $355.

The markup is $130/$355 = 36.62%.

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A gardener is planning to fill her garden with mulch. She plots it on a grid to plan how much she will need. The garden is in th

tester [92]

First we need to know the total area. Since this is a rectangle we need two adjacent sides and we can find these from vertex pairing:

Matching y: (3,9) --> (5,9) = 2 ft
Matching x: (3,9) --> (3,3) = 6 ft

Area = l*w = 2*6 = 12 square ft

# of bags = 12sqft/(5sqft/bag) = 2.4 bags.

Cost = $5.00 * 2.4 = $12 (notice that it cost $1 to cover 1sqft so we could have skipped a step here.)

NOTE: In the real world she probably can't buy just 0.4 of a bag and would actually have to buy three full bags for $15.

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2 years ago

choose the equivalent system of linear equations that will produce the same solution as the one given below. 4x − 2y = 6 2x y =

Julli [10]

<span>4x − 2y = 6 . . . . . (1)
2x + y = 5 . . . . . (2)

(2) x 2 => 4x + 2y = 10 . . . . . (3)

(1) - (3) gives: -4y = -4
y = -4/-4 = 1

From (2), 2x + 1 = 5 => 2x = 5 -1 = 4
x = 4/2 = 2

Solution is (2, 1)

Substituting the solution into the options gives that
</span><span>−4x − 2y = 10
−4y = 4 −4x
has the same solution.
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2 years ago

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Margo deposited $100 into a savings account earning 4.5% simple annual interest. At the end of each year, she adds $100 to her a

nadezda [96]

Answer:

principal interest total money in account

at the end of year

Year one $100 $4.5 $104.5

year two $200 $ 9 +$4.5 $ 213.5

year three $300 $ 9 +$4.5 + $13.5 $ 327

Step-by-step explanation:

Simple interest for any principal is given by

I = p* r* t/100

I = interest rate accrued on principle amount

p is the amount deposited

r is the rate of interest

t is the time period of saving

_______________________________________________

For year one

p = $100

r = 4.5%

t=1

I = 100*4.5*1/100 = 4.5

_______________________________________________

For year two $100 more is added to already existing $100 in account.

p = 100 +100 = $200

r = 4.5%

t=1

I = 200*4.5*1/100 = 9

_______________________________________________

For year two $100 more is added to already existing $200 in account after two years.

p = 100 +100 +100 = $300

r = 4.5%

t=1

I = 300*4.5*1/100 = 13.5

_______________________________________________

There fore total money in Margo account is

$300 saving deposited by her

$4.5 + $9 + $13.5 = $27 (interest accrued in three time)

Formulating the results in tabular form

principal interest total money in account

at the end of year

Year one 100 4.5 104.5

year two 200 9 +4.5 213.5

year three 300 9 +4.5 + 13.5 327

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2 years ago

You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week

aliya0001 [1]

Answer:

$q = -6p + 104$

Step-by-step explanation:

Linear function:

A linear function has the following format:

$q = mp + b$

In which m is the slope and b is the q-intercept.

One week you charged $4 per guest and averaged 80 guests per night. The next week you charged $10 per guest and averaged 44 guests per night.

This means that we have these following points: (4,80), (10,44).

Finding the slope:

With a pair of points, the slope is given by the change in q divided by the change in p.

Change in q: 44 - 80 = -36

Change in p: 10 - 4 = 6

Slope: $m = \frac{-36}{6} = -6$

So

$q = -6p + b$

Finding b:

We replace one of the points. Replacing (4,80).

$q = -6p + b$

$80 = -6*4 + b$

$b = 104$

So

$q = -6p + 104$

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2 years ago

Mike forgot to replace the cap on a bottle of room freshener. The room freshener began to evaporate at the rate of 15% per day.

aleksandrvk [35]

Given:
bottle of room freshener = 40 grams
evaporates at the rate of 15% per day.

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2 28.9
3 24.57
4 20.88
5 17.75

<span>graph of exponential function going down from left to right in quadrant 1 through the point 0, 40 and approaching the x axis</span>

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2 years ago

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