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Fynjy0 [20]
2 years ago
9

What is the energy equivalent of an object with a mass of 2.5 kg? 5.5 × 108 J 7.5 × 108 J 3.6 × 1016 J 2.25 × 1017 J

Physics
2 answers:
k0ka [10]2 years ago
6 0
We can use the Einsten's relation which states the equivalence between mass and energy:
E=mc^2
where
E is the energy
m is the rest mass of the object
c is the speed of light

By using this formula and m=2.5 kg, we can find the equivalent energy of the object:
E=mc^2 = (2.5 kg)(3 \cdot 10^8 m/s)^2=2.25 \cdot 10^{17} J
Brums [2.3K]2 years ago
6 0

The answer is D. 2.25 × 1017 J

You might be interested in
Which of the following statements is/are true? Check all that apply. Check all that apply. Power is the rate at which energy is
AlladinOne [14]

Answer:

True statements:

Power is the rate at which work is done.

Power is the rate at which energy is transformed.

The SI unit of power is watt.

A person is limited in the total work he or she can do by the rate at which energy can be transformed.

Explanation:

The above statements are true.

1. Power is defined as the rate at which work is done.

2. Power is the rate at which energy is transformed. Whenever energy changes its form, or moves from one place to another, the rate at which it makes those changes is described as power.

3. The SI Unit of power is watts.  If 1 joule of energy is converted by an object in 1 second then its power is called one watt.

So, the statement<em> 'the SI unit of power is the horsepower' is</em> false.

4. A person is limited in the total work he or she can do by the rate at which energy can be transformed i.e, his power. He is not only limited by the total energy required.

So, the statement <em>'A person is limited in the total work he or she can do only by the total energy required'</em> is not completely true.

5 0
2 years ago
What is the total flux φ that now passes through the cylindrical surface? enter a positive number if the net flux leaves the cyl
trasher [3.6K]

Net flux through the cylindrical surface is given as

\phi = \frac{q}{epsilon_0}

here q = enclosed charge in the surface

so here in order to find the value of q

q = \lambda* L

so now we have

\phi = \frac{\lambda * L}{\epsilon_0}

so this is the total flux

now by Gauss's law we can find the electric field

\int E.dA = \phi

\int E.dA = \frac{\lambda * L}{\epsilon_0}

E* 2\pi rL = \frac{\lambda * L}{epsilon_0}

E = \frac{\lambda}{2\pi \epsilon_0 r}

<em>by above expression we can find the electric field at required position</em>

8 0
2 years ago
Some gliders are launched from the ground by means of a winch, which rapidly reels in a towing cable attached to the glider. Wha
aliina [53]

Answer:

P=627.47W

Explanation:

To solve this problem we have to take into account, that the work done by the winch is

W=Fh

the force, at least must equal the gravitational force

F=Mg=(156kg)(9.8\frac{m}{s^2})=1258.8N

with force the tension in the cable makes the winch go up.

The work done is

W=(1258.8N)(58.0m)=73010.4J

To calculate the power we need to know what is the time t. But first we have to compute the acceleration

The acceleration will be

v_f^2=v_0+2ah\\a=\frac{v_f^2}{2h}=\frac{(24.9\frac{m}{s})}{2(58.0m)}=0.214\frac{m}{s^2}

and the time t

v_f=v_0+at\\t=\frac{v_f}{a}=116.35s

The power will be

P=\frac{W}{t}=\frac{73010.4J}{116.35s}=627.47W

HOPE THIS HELPS!!

6 0
2 years ago
A satellite with a mass of 5.6 E 5 kg is orbiting the Earth in a circular path. Determine the satellite's velocity if it is orbi
solniwko [45]

Answer:

7500 m/s

Explanation:

Centripetal acceleration = gravity

v² / r = GM / r²

v = √(GM / r)

Given:

G = 6.67×10⁻¹¹ m³/kg/s²

M = 5.98×10²⁴ kg

r = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m

v = √(6.67×10⁻¹¹ (5.98×10²⁴) / (7.037×10⁶))

v = 7500

The orbital velocity is 7500 m/s.

7 0
2 years ago
The volume V of a python egg is given by the formula V=43πabc. For some python eggs, a=2a=2 inches, b=2b=2 inches, and c=3c=3 in
NARA [144]

Answer:

V=516πin^2

Explanation:

you must replace a, b, and c in the first formula for the python egg

a=2inches

b=2inches

c=3inches

REPLACING IN THE ORIGINAL EQUATION

V=43πabc

V=43π(2)(2)(3)

V=43(12)π

V=516πin^2

The volume of the piton egg is 516π in^2

4 0
2 years ago
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