The number of particles that are in 12.7 moles of compound that Jessica had is 7.65 x10^24 particles of compound ( answer E)
<u><em>Calculation</em></u>
<u><em> </em></u>The number of particles are calculated using the Avogadro's Principle constant.
- that is according to Avogadro's 1 moles = 6.02 x10^23 particles
what about 12.7 moles of compound= ? particles\
by use of cross multiplication
- number of particles of compound= [12.7 moles x (6.02 x 10^23)] / 1 mole = 7.65 x 10^24 particles of compound ( answer E)
N.b moles and moles cancels each other
Answer:

Explanation:
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In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:

In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:

Thus, we plug in the given data to obtain:

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The final temperature of the lead-water system will be lower than the final temperature of the copper-water system.
Answer:
The over all reaction :
The standard cell potential of the reaction is 0,.897 Volts.
Explanation:
Reduction at cathode :
..[1]

Reduction potential of
to 
Oxidation at anode:
.[2]

Reduction potential of
to 
To calculate the
of the reaction, we use the equation:

Putting values in above equation, we get:


The over all reaction : 2 × [1] + [2]
The standard cell potential of the reaction is 0,.897 Volts.
It matches the universal pH indicator and is indicating the proper pH