ΔS of the object : <u>0.085324 J mol/K</u>
<h3>Further explanation </h3>Entropy (with the symbol S) in thermodynamics indicated the degree of system disorder
Entropy like other thermodynamic terms can only be calculated from the initial and final changes
Entropy will also change in the process of changing energy forms
The value of ΔS ° can be calculated from standard entropy data
<h3>∆S ° (reaction) = ∑S ° (product) - ∑ S ° (reagent) </h3>Entropy can also be calculated from the change in heat (ΔQ) to temperature (T), under Isothermal process (constant temperature) conditions
From this equation it can be seen that entropy will rise if the temperature gets lower (hot to cold)
An object at 20°C absorbs 25.0 j of heat
T = 20 + 273 = 293 K
ΔQ = 25 J
then:
Entropy: ΔS =
Delta H solution
an exothermic reaction
as endothermic or exothermic
an exothermic dissolving process
Answer:
Speed of water, v = 4.2 m/s
Explanation:
Given that,
Diameter of the tank, d = 17 cm
It is placed at a height of 90 cm, h = 0.9 m
We need to find the speed at which the water exits the tank through the hole. It can be calculated using the conservation of energy as :
v = 4.2 m/s
So, the speed of water at which the water exits the tank through the hole is 4.2 m/s. Hence, this is the required solution.
Answer:
15.1°
Explanation:
The horizontal velocity of the hockey puck is constant during the motion, since there are no forces acting along this direction:
Instead, the vertical velocity changes, due to the presence of the acceleration due to gravity:
(1)
where
is the initial vertical velocity
g = 9.8 m/s^2 is the gravitational acceleration
t is the time
Since the hockey puck falls from a height of h=2.00 m, the time it needs to reach the ground is given by
Substituting t into (1) we find the final vertical velocity
where the negative sign means that the velocity is downward.
Now that we have both components of the velocity, we can calculate the angle with respect to the horizontal: