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2 years ago

Why would it be incorrect to balance the equation by changing NaOH to Na2OH2 instead of 2NaOH

1 answer:

6 0

Beacuse Na2OH 2 is completely different compound than 2NaOH.

By NaOH we mean two molecules with one sodium, one hydrogen and one oxygen atom each.

But by Na2OH2 it'll be understood that 2 atoms of sodium one aton of oxygen and 2 arom of hydrogen was used ro make up this one molecule.

Here's a simple example,

You have
H2+ O2 ---------> H2O

while balancing,

you're supposed to write H2O as 2H2O
which means 2 molecules of water.

And when you write it as H2O2 insted it means that you are forming and oxidizing and reducing agent, which is a waste (toxic waste) for our body and can kill us, which means it has the opposite property of water.

And this is the reason why you should balance it by placing the numbers on the far left side than subsripting it below atom of different elements so that you can make the same compund everytime.

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Anastasy [175]

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2 years ago

Give the product for the reaction of 1-butene with methanol in the presence of acid. The mechanism is the same as the mechanism

Nuetrik [128]

Answer:

The final result is 2-methoxybutane.

Explanation:

1-butene has a carbon-carbon double bound between C1 and C2.

When it will react with methanol, in the presence of an acid, the result will be an ether.

C4H8 + CH3OH → C5H12O

An acid-catalyzed ether synthesis from alkenes is limited by carbocation stability.

In the first step, the double bound will disappear. The C2 atom will be a C+ atom, this becaus it has only 3 bounds and not 4.

This C+ -atom will atract the O- atom to form an ether. The CH3 of methanol will bind on the C3 atom, this is the most stable position.

2-methoxybutane will be formed. It has a structural formula of C5H12O

1-methoxybutane will not be formed, because it's less stable.

1-butanol will be formed when water is added to 1-butene. The mechanism has the same principle but not the same product.

1-ethoxybutane and 2-ethoxybutane have a structural formula of C6H14O, this will not be the final result.

The final result is 2-methoxybutane.

8 0

2 years ago

In a container containing co, h2, and o2, what is the mole fraction of co if the h2 mole fraction is 0.22 and the o2 mole fracti

almond37 [142]

Thank you for posting your question here at brainly. The mole fraction of co if the h2 mole fraction is 0.22 and the o2 mole fraction is 0.58 is 0.20, below is the solution:

mole fraction CO + mole fraction H2 + mole fraction O2 = 1

mole fraction CO = 1 - ( 0.22 + 0.58)=0.20

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2 years ago

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Veronika [31]

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2 years ago

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Predict all bond angles in the following compound. Be sure to answer all parts. HCa≡CbCcH2OH

morpeh [17]

Answer:

See explanation below

Explanation:

What we have to consider is the hybridation of the three carbon atoms we are asked in this question .

Hybridization # bonds Angle

sp³ 4 109.5º

sp² 3 + 1 pi bond 120º

sp 2 + 2 pi bonds 180º

Carbon atom (a) is bonded to two atoms: Carbon (b) and one Hydrogen. It has a triple bond to Carbon (b). Therefore its hybridization is sp with two pi bonds, and for sp hybridization we know the angle is 180 º.

The same hybridization sp happens to carbon (b) bonded to Carbon (c) and C(a) using one sp bond to Carbon (a) and 2 pi bonds; it is also bonded using the other sp to Carbon (c). The angle is therefore 180 between Carbons b and c.

Carbon C is bonded to 4 atoms, therefore, its hybridization is sp³ and the angles with these 4 atoms will be 109.5 º tehedral ( one bond to OH, one to C(b), and 2 to H ) .

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2 years ago