Answer:
The disadvantages of each of the given model of electron configuration have been mentioned below:
1). Dot Structures - They take up excess space as they do not display the electron distribution in orbitals.
2). Arrow and line diagrams make the counting of electrons and take up too much space.
3). Written Configurations do not display the electron distribution in orbitals and help in lose counting of electrons easily.
Answer:
The reducing agent is Zn.
Explanation:
Let's consider the reaction between zinc and hydrochloric acid.
Zn(s) + 2 HCl(aq) ⇄ ZnCl₂(aq) + H₂(g)
This is a redox reaction, which can be divided in 2 half-reactions: reduction and oxidation.
In the reduction, H⁺ gains electrons and it is considered the oxidizing agent.
2H⁺ + 2 e⁻ ⇒ H₂
In the oxidation, Zn loses electrons and it is considered the reducing agent.
Zn ⇒ Zn²⁺ + 2 e⁻
<span>A balanced chemical equation for the standard formation reaction of solid potassium dichromate is;
</span><span>K</span>₂<span>Cr</span>₂<span>O</span>₇→<span>K</span>⁺<span>(s) + KCr</span>₂<span>O</span>₇⁻<span>(s)</span>
Potassium dichromate with a chemical formula K₂Cr₂O₇ with molar mass 294.185 g/mol, is a common inorganic chemical reagent and its common use is as an oxidizing agent. It is odorless and its appearance is red-orange crystalline solid.
The heat produced by combustion per liter of methanol is calculated as follows
heat released = moles x heat of combustion of methanol
heat of combustion of CH3OH = 715 kj/mol
calculate moles first
that is ,moles =mass/molar mass
calculate the mass = density x volume(1L=1000ml)
= 0.791 x1000=791 g
molar mass of CH3Oh = 32g/mol
moles is therefore= 791 g / 32g/mol = 24.72moles
heat released is therefore= 24.72mole x 715 Kj/mol =17673.91 KJ
Answer:
Explanation:
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