If the pOH of vinegar is 9.45, what is its [OH− ]?

2 answers:

4 0

Answer:
[OH⁻] = 3.54 × 10⁻¹⁰ M

Solution:

pOH is related to [OH⁻] as,

pOH = - log [OH⁻]

Putting value of pOH,

9.45 = -log [OH⁻]

Solving for [OH⁻],

[OH⁻] = 10⁻⁹·⁴⁵ ∴ 10 = Antilog

[OH⁻] = 3.54 × 10⁻¹⁰ M

Rainbow [258]2 years ago

3 0

Answer:

3.55 and -10

Explanation:

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