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Vilka [71]
2 years ago
10

A student Increases the temperature of a 417 cubic centimeter balloon from 278 K to 231 K. Assuming constant pressure what shoul

d the new volume of the balloon be
Chemistry
1 answer:
WITCHER [35]2 years ago
5 0
Initial Conditions:
Volume= v1= 417 cm³
Temperature= T1 = 278 K
 
Final Conditions:
Temperature= T2 = 231K
Volume = v2 =?

Use the general gas equation;

                                        P1*v1/T1 =  P2*v2/T2
As, the temperature is constant;
 So,
                                               v1/T1 = v2/T2
                                              417/278 = v2/231
                                                  v2= 346.5 cm³                                           
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Andrew plays trumpet in the concert band. He holds the trumpet still at his side until it is time for him to play. When it is ti
Tom [10]

Answer:

Explanation:

The first law is An object won't move by itself, and once in motion, it won't stop unless some force acts upon it. With this being said when the trumpet is at his side and he is not holding it will not move not until he lets go of it.

6 0
2 years ago
Read 2 more answers
What pressure does 3.54 moles of chlorine gas at 376 k exert on the walls of it 51.2 l container? I'm Lazy sooooo
Lilit [14]

Answer:

The answer to your question is P = 2.13 atm

Explanation:

Data

Pressure = ?

number of moles = 3.54

Temperature = 376 °K

Volume = 51.2 L

R = 0.08205 atm L/mol°K

Formula

PV = nRT

- Solve for P

  P = nRT / V

- Substitution

  P = (3.54)(0.08205)(376) / 51.2

- Simplification

  P = 109.21 / 51.2

Result

 P = 2.13 atm  

6 0
1 year ago
Determine the overall charge on particles with the subatomic makeups given.
Gwar [14]

Answer:

The correct solution will be "+3".

Explanation:

The given values are:

Number of protons

= 13

Number of neutrons

= 14

Number of electrons

= 10

As we know,

⇒  Charge = Number \ of \ protons - Number \ of \ electrons

On putting the estimated values, we get

⇒               =13 - 10

⇒               =+3

5 0
2 years ago
Coal gasification is a multistep process to convert coal into cleaner-burning fuels. In one step, a coal sample reacts with supe
ddd [48]

Answer :

The enthalpy of reaction is, -187.6 kJ/mol

The total heat will be, -2251 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(a) The formation of CH_4 will be,

2C(coal)+2H_2O(g)\rightarrow CH_4(g)+CO_2(g)    \Delta H_{rxn}=?

The intermediate balanced chemical reaction will be,

(1) C(coal)+H_2O(g)\rightarrow CO(g)+H_2(g)     \Delta H_1=29.7kJ

(2) CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)    \Delta H_2=-41kJ

(3) CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)    \Delta H_3=-206kJ

We are multiplying equation 1 by 2 and then adding all the equations, we get :

(b) The expression for enthalpy of reaction will be,

\Delta H_{rxn}=2\times \Delta H_1+\Delta H_2+\Delta H_3

\Delta H_{rxn}=(2\times 29.7)+(-41)+(-206)

\Delta H_{rxn}=-187.6kJ/mol

Therefore, the enthalpy of reaction is, -187.6 kJ/mol

(c) Now we have to calculate the total heat.

\Delta H=\frac{q}{n}

or,

q=\Delta H\times n

where,

\Delta H = enthalpy change = -187.6 kJ/mol

q = heat = ?

n = number of moles of coal = \frac{1.00\times 1000g}{12.00g/mol}=83.33mol

Now put all the given values in the above formula, we get:

q=(-187.6kJ/mol)\times (83.33mol)=-2.251kJ

Thus, the total heat will be, -2251 kJ

4 0
2 years ago
The population of rabbits in a forest is decreasing. Foxes in that region are now competing with each other for the limited numb
sveta [45]
Rabbits are eaten by predators such as foxes and wild dogs. If rabbit number decline predators ( foxes ) compete for the rest of the resources in forest. This is the competition between the members of same species or : interspecific competition. Foxes compete for the same resource ( rabbits ).
Answer: Interspecific competition.  
6 0
1 year ago
Read 2 more answers
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