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2 years ago

If a solution process is exothermic, how does the energy required for dissolving the solute compare with the energy released?

1 answer:

8 0

The correct answer would be the third option. If a solution process is exothermic, the energy required is less than the energy released. An exothermic reaction is a reaction that releases energy to the surroundings. The energy released should be more than what is absorbed in order to maintain the reaction.

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Plzzz help...

Anna [14]

Answer:

just answer this and you will have yours

Explanation:Find the area of a circle with a diameter of \color{green}{16}16start color green, 16, end color green.

Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and enter your answer as a decimal.

8 0

1 year ago

Mr. Rutherford's chemistry class was collecting data in a neutralization study. Each group had 24 test tubes to check each day f

ycow [4]

I’m pretty sure it is A at least that’s what we did at our school to test this

6 0

2 years ago

A student has 100. mL of 0.400 M CuSO4 (aq) and is asked to make 100. mL of 0.150 M CuSO4 (aq) for a spectrophotometry experimen

GenaCL600 [577]

Answer:

We have to take 37.5 mL of a 0.400 M solution

Explanation:

Step 1: Data given

Stock volume = 100 mL = 0.100L

Stock concentration 0.400 M

Volume of solution he wants to make = 100 mL = 0.100L

Concentration of solution he wants to make = 0.150 M

Step 2: Calculate the volume of 0.400 M CuSO4 needed

C1*V1 = C2*V2

⇒with C1 = the stock concentration = 0.400M

⇒with V1 = the volume of the stock = TO BE DETERMINED

⇒with C2 = the concentration of the solution he wants to make = 0.150 M

⇒with V2 = the volume of the solution made = 0.100 L

0.400 M * V1 = 0.150M * 0.100L

V1 = (0.150M*0.100L) / 0.400 M

V1 = 0.0375 L = 37.5 mL

We have to take 37.5 mL of a 0.400 M solution

5 0

2 years ago

Read 2 more answers

`suppose you were tasked with producing some nitrogen monoxide (a.k.a. nitric oxide). i'm sure this is often requested of you. y

Umnica [9.8K]

N(H₂O):n(NO)=6:4(3:2), n(NO)=2·3,5mol÷3=2,33mol
So it is a).

7 0

2 years ago

Read 2 more answers

Calculate the amount of work done against an atmospheric pressure of 1.00 atm when 500.0 g of zinc dissolves in excess acid at 3

ZanzabumX [31]

Answer:

19,26 kJ

Explanation:

The work done when a gas expand with a constant atmospheric pressure is:

W = PΔV

Where P is pressure and ΔV is the change in volume of gas.

Assuming the initial volume is 0, the reaction of 500g of Zn with H⁺ (Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)) produce:

500,0g Zn(s)× $\frac{1molZn}{65,38g}$ × $\frac{1molH_{2}(g)}{1molZn}$ = 7,648 moles of H₂

At 1,00atm and 303,15K (30°C), the volume of these moles of gas is:

V = nRT/P

V = 7,648mol×0,082atmL/molK×303,15K / 1,00atm

V = 190,1L

That means that ΔV is:

190,1L - 0L = <em>190,1L</em>

And the work done is:

W = 1atm×190,1L = 190,1atmL.

In joules:

190,1 atmL× $\frac{101,325}{1atmL}$ = <em>19,26 kJ</em>

I hope it helps!

5 0

2 years ago