There are 20 students on the varsity baseball team. Nine of the students will be on the starting lineup. The coach calls out the
2 answers:
Answer: 167,960
Step-by-step explanation:
Number of combinations of n things taking r at a time is given by :-
Given : There are 20 students on the varsity baseball team.
9 of the students will be on the starting lineup.
The coach calls out the names of the players on the list in no particular order (so we use combinations).
Then, the number of different list of students could be read is given by :-
Hence, the number of different list of students could be read= 167,960
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Answer:
See attachment.
Step-by-step explanation:
The given functions are:
and g(x)=-1
To find the x-value of the point of intersection of the two functions, we equate the two functions and solve for x.
The graph that shows the input value for which f(x)=g(x) is the graph which shows the point of intersection of f(x) and g(x) to be at x=-2.
We have to write an equation that uses this info so we can find the cost to ship that package. However, the package weight is given to us in grams and we need it in ounces. So first thing we are going to do is convert that 224 g to ounces. Use the fact that 1 g = .035274 ounces to convert. . Do the multiplication and cancel out the label of grams and we have 7.901376 ounces. Ok. We know that it costs .57 to mail the package for the first ounce. We have almost 8 ounces. So no matter what, we are paying .57. For each additional ounce we are paying .32. The number of .32's we have to spend depends upon how much the package goes over the first ounce. For the first ounce we pay .57, then for the remaining 6.901376 ounces we pay .32 per ounce. Our equation looks like this: C(x) = .32(6.901376) + .57 and we need to solve for the cost, C(x). Doing the multiplication we find that it would cost $2.78 to ship that package.
Answer:
(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).
(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).
(c) First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).
Step-by-step explanation:
(a)
Let <em>X</em> = number of dog owners who take more pictures of their dog than of their significant others or friends.
Given:
<em>X</em> = 610
<em>n</em> = 1000
Confidence level = 90%
The (1 - <em>α</em>)% confidence interval for population proportion is:
The sample proportion is:
The critical value of <em>z</em> for a 90% confidence level is:
Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:
Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).
<u>Interpretation</u>:
There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).
Correct option is (3).
(b)
Let <em>X</em> = number of dog owners who are more likely to complain to their dog than to a friend.
Given:
<em>X</em> = 440
<em>n</em> = 1000
Confidence level = 95%
The (1 - <em>α</em>)% confidence interval for population proportion is:
The sample proportion is:
The critical value of <em>z</em> for a 95% confidence level is:
Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:
Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend is (0.42, 0.46).
<u>Interpretation</u>:
There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).
Correct option is (1).
(c)
The confidence interval in part (b) is wider than the confidence interval in part (a).
The width of the interval is affected by:
- The confidence level
- Sample size
- Standard deviation.
The confidence level in part (b) is more than that in part (a).
Because of this the critical value of <em>z</em> in part (b) is more than that in part (a).
Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.
First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).