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ElenaW [278]
1 year ago
10

The yearbook club has 5 members returning from last year. They set up a booth in the cafeteria to recruit more members, and an a

verage of 3 new members sign up each day. Which best describes why the graph relating the total number of members on the yearbook club, m, and the number of days the booth is set up, d, will be continuous or discrete?
Mathematics
2 answers:
Drupady [299]1 year ago
8 0
The graph will go up
NISA [10]1 year ago
7 0

Answer:

It will be discrete.

Step-by-step explanation:

The yearbook club has 5 members returning from last year.

An average of 3 new members sign up each day.

This means each following day the members increase with 3.

We can represent this information in an equation as:

m=5+3d

And the series will form like : 5,8,11,14,17........

Hence, we can say that the graph will be a discrete function as the members will be whole numbers and not partial and the booth is also set up once every day,

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Tumor counts: A cancer laboratory is estimating the rate of tumorigenesis in two strains of mice, A and B. They have tumor count
Igoryamba

Answer:

The observed tumor counts for the two populations of mice are:

Type A mice = 10 * 12 = 120 counts

Type B mice = 13 * 12 = 156 counts

Step-by-step explanation:

Since type B mice are related to type A mice and given that type A mice have tumor counts that are approximately Poisson-distributed with a mean of 12, we can then assume that the mean of type A mice tumor count rate is equal to the mean of type B mice tumor count rate.

This is because the Poisson distribution can be used to approximate the the mean and variance of unknown data (type B mice count rate) using known data (type A mice tumor count rate).  And the Poisson distribution gives the probability of an occurrence within a specified time interval.

3 0
2 years ago
Orin solved an equation and justified his steps as shown in the table.
sergij07 [2.7K]

Answer:

Step-by-step explanation:

Given the equation as

\frac{3x}{5} -3=12

apply multiplication property of equality where you multiply every term by 5

\frac{3x}{5}*5 -3*5=12*5

3x-15=60------------------apply addition property of equality

3x-15+15=60+15

3x=75--------------------------appy division property of equality by dividing both sides by 3

3x/3=75/3

x=25

6 0
2 years ago
The Tennessee Tourism Institute (TTI) plans to sample information center visitors entering the state to learn the fraction of vi
baherus [9]

Answer: 2185

Step-by-step explanation:

Let p be the proportion of visitors are campers.

Given : The Tennessee Tourism Institute (TTI) plans to sample information center visitors entering the state to learn the fraction of visitors who plan to camp in the state.

The prior proportion of visitors are campers : p=0.35

Allowable error : E= 2%= 0.02

We know that the z-value for 95% confidence = z_c=1.96

Then by Central Limit Theorem , the required sample size would be :

n=p(1-p)(\dfrac{z_{c}}{E})^2

\Rightarrow\ n=0.35(1-0.35)(\dfrac{1.96}{0.02})^2\\\\ n= 0.35(0.65)(9604)

Simply , we get

n=2184.91\approx2185  [Rounded to the next whole number.]

Hence, the smallest sample size to estimate the population proportion of campers =2185

7 0
2 years ago
A local city collects 8% sales tax. If the total purchase was $216.00, then how much was collected for sales tax?
Phantasy [73]
$216 x 0.08 = $17.28.
Therefore $17.28 was collected for sales tax.
4 0
1 year ago
Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
Dovator [93]

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
2 years ago
Read 2 more answers
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