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solmaris [256]
2 years ago
15

Nanotechnology and microtechnology devices are both very tiny. However, one property of nanotechnology distinguishes it from mic

rotechnology. What is this unique property? Nanotechnology can create new products. Nanotechnology is not affected by gravity. Nanotechnology travels at the speed of light if needed. Nanotechnology can display wave-particle duality.
Physics
1 answer:
jek_recluse [69]2 years ago
7 0
Nanotechnology displays particle quality
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In which of the following color gradient types does the linear gradient gets mirrored on either side of the starting point?
Travka [436]

Answer: Reflected  

Explanation: Color Gradient refers to the variety of position dependent (as the vary with position) colors which are used to fill a region. Gradient is a mixture of two or more colors. This blend of colors adds depth to the design.

Types of color gradient are

  • Linear: The color blends in a straight from starting to ending point
  • Radial: The color transitions from starting point to ending a circular pattern.
  • Angle: It glides counterclockwise around starting point.
  • Diamond: It makes a diamond shape from starting point and its ending point is one corner of diamond.
  • Reflected: In this color gradient type symmetric linear gradient gets mirrored on either side of the starting point. This type of color gradient can be used to depict a lead pipe.

4 0
2 years ago
A -4.00 nC point charge is at the origin, and a second -5.50 nC point charge is on the x-axis at x = 0.800 m.
mafiozo [28]

Answer:

a. f=1.22*10^{-15} N

b. f=53.6*10^{-17} N

Explanation:

The force existing between two charges is given as

f=\frac{kq_{1}q_{2}}{r^{2}}

where q= charge,

k=constant

r= distance between the two charges

Note: this force can either be repulsive or attractive force depending on the charges involve. it is repulsive if they are similar charge and it is attractive if it is opposite charges.

Also the charge of an electron is

-1.602*10^{-19}

A. we first determine the magnitude force between the -4nC and the electron

f_{21}=\frac{kq_{1}q_{2}}{r^{2}}\\f_{21}=\frac{9*10^{10} 4*10^{-9} *1.602*10^{-19} }{0.2^{2}}\\f_{21}=\frac{57.67*10^{-18} }{0.04}\\f_{21}=1.44*10^{-15}Ni

this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis

for the -5.50nC the distance between them is 0.600m as can be seen in the diagram the magnitude of the force is

f_{23} =\frac{kq_{1}q_{2}}{r^{2}}\\f_{23}=\frac{9*10^{10} 5.50*10^{-9} *1.602*10^{-19} }{0.6^{2}}\\f_{23}=\frac{79.3*10^{-18} }{0.36}\\f_{23}=-(0.22*10^{-15})N i

this this force will be repulsive force and it points away from the electron i.e points towards the -ve x-axis.

The total net force on the electron is thus

f=f_{21}+f_{23}\\ f=1.44*10^{-15}-0.22*10^{-15}\\  f=1.22*10^{-15} N

b. at  distance of x=1.20m, this is shown on the diagram below (attachment 2)

we first determine the magnitude force between the -4nC and the electron

f_{21}=\frac{kq_{1}q_{2}}{r^{2}}\\f_{21}=\frac{9*10^{10} 4*10^{-9} *1.602*10^{-19} }{1.2^{2}}\\f_{21}=\frac{57.67*10^{-18} }{1.44}\\f_{21}=4.0*10^{-17}Ni

this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis.

for the -5.50nC the distance between them is 0.4m as can be seen in the diagram the magnitude of the force is

f_{23} =\frac{kq_{1}q_{2}}{r^{2}}\\f_{23}=\frac{9*10^{10} 5.50*10^{-9} *1.602*10^{-19} }{0.4^{2}}\\f_{23}=\frac{79.3*10^{-18} }{0.16}\\f_{23}=49.6*10^{-17}Ni

this this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis.

The total net force on the electron is thus

f=f_{21}+f_{23}\\ f=4.0*10^{-15}+49.6*10^{-17}\\  f=53.6*10^{-17} N

8 0
2 years ago
How many ternary strings of length 2 n are there in which the zeroes appear only in odd-numbered positions?
Rashid [163]

In a string of length 2n, there are exactly n odd-numbered posiitons. In the remaning n even-numbered positions, we want to choose from only two possible digits, either a 1 or a 2. This means there are 2^n such ternary strings.

8 0
2 years ago
I WIL A 2.00-kg object traveling east at 20.0 m/s collides with a 3.00-kg object traveling west at 10.0 m/s. After the collision
pishuonlain [190]
Using the following given values:

Object 1:
Mass = M1 = 2 kg
Velocity before collision = Vb1 = 20 m/s
Velocity after collision = Va1 = -5 m/s 

Object 2:
Mass = M2 = 3 kg
Velocity before collision = Vb2 = -10 m/s
Velocity after collision = Va2 = ? m/s<span> 
</span>
Obtaining Va2 via law of conservation of momentum:

total momentum after collision = total momentum before collision
M1 * Va1 + M2 * Va2 = M1 * Vb1 + M2 * Vb2
2*-5 + 3Va2 = 2*20 + 3*-10
Va2 = 6.67

Total kinetic energy before collision:

KE1 = (1/2)*M1*Vb1^2 + (1/2)*M2*Vb2^2
<span>KE1 = (1/2)*2*(20)^2 + (1/2)*3*(-10)^2
KE1 = 550 J

</span>Total kinetic energy after collision:

KE2 = (1/2)*M1*Va1^2 + (1/2)*M2*Va2^2
<span>KE2 = (1/2)*2*(-5)^2 + (1/2)*3*(6.67)^2
KE2 = 91.73 J
</span>
Total kinetic energy lost:

Energy lost = KE1 - KE2 = 550 - 91.73 = 458.27 J
4 0
2 years ago
In grassland regions, rainy seasons and drought seasons determine, in part, the _____. kinds of resident organisms spread of fir
qaws [65]

kinds of resident organisms
6 0
2 years ago
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