Answer:
Explanation:
Mass of a hockey puck, m = 0.17 kg
Force exerted by the hockey puck, F' = 35 N
The force of friction, f = 2.7 N
We need to find the acceleration of the hockey puck.
Net force, F=F'-f
F=35-2.7
F=32.3 N
Now, using second law of motion,
F = ma
a is the acceleration of the hockey puck
So, the acceleration of the hockey puck is 
.
Please provide the choices to select the possible choices.
Color <span>is a physical property of all visible light determined by the light's frequency and visible to the human eye.</span>
Answer:
Explanation:
3. Newton’s third law explains how every action has an equal but opposite reaction, meaning that forces comes in pairs. While the locomotive’s wheels are pushing back against the ground as the action force, the ground is producing a reaction force towards the locomotive, propelling it forward. Another pair of forces that act on the locomotive is gravity and normal force. While gravity is pulling the locomotive towards the ground, the normal force the ground exerts on the locomotive is why the locomotive doesn’t fall through the ground.
4. The force of Earth’s gravity on the Sun is weaker than the force of the Sun’s gravity on Earth. The Sun’s attraction affects the motion of Earth more than the Earth’s attraction affects the Sun’s motion because according to Newton’s second law, force has mass as one of its factors. The Sun has a significantly higher mass than Earth, meaning that its force of gravity would also be significantly higher. Newton’s third law is why the Earth doesn’t get marginally closer to the Sun, stating that every action has an equal and opposite reaction. As the Sun is pulling Earth towards itself, Earth is pulling away from the Sun.
Answer:
86.4 N downward
Explanation:
Force: This can be defined as the product of mass and acceleration of a body.
The S.I unit of Force is Newton(N).
The Expression of force is given as,
F = ma ................ Equation 1
Where F = force of the parachute harness, m = mass of the skydiver, a = acceleration of the skydiver.
Given: m = 72 kg, a = 1.2 m/s²
Substitute into equation 1
F = 72(1.2)
F = 86.4 N down ward.
Hence the force on the parachute harness = 86.4 N downward
