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Aleks04 [339]
2 years ago
14

a footballer kicks a ball vertically upwards. initially, the ball is stationary. his boot is in contact with the ball for 0.05s.

the average resultant force on the ball during this time in 180N. the ball leaves his foot at 20m/s. calculate the height to which the ball rises. ignore air resistance.
Physics
2 answers:
taurus [48]2 years ago
8 0
Kick Ball force average 200
lozanna [386]2 years ago
4 0

Answer:

The ball rises to a height of 20.4 meters.

Explanation:

Since we know the speed at which the ball starts rising, we can ignore the other data. The height reached by the ball can be obtained using the kinematics equation:

v^{2}=v_0^{2}-2gy

Since the velocity at the highest point is zero, we can solve for the height y at that point:

y=\frac{v_0^{2}}{2g}

Plugging in the given value for the initial velocity, and assuming that the acceleration due to gravity g is 9.8m/s², we obtain:

y=\frac{(20m/s)^{2}}{2(9.8m/s^{2})}\\\\y=20.4m

It means that the ball rises to a height of 20.4 meters.

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Maria throws an apple vertically upward from a height of 1.3 m with an initial velocity of +2.8 m/s. Will the apple reach a frie
evablogger [386]

Answer:

No, the apple will reach 4.20041 m below the tree house.

Explanation:

t = Time taken

u = Initial velocity = 2.8 m/s

v = Final velocity = 0

s = Displacement

g = Acceleration due to gravity = -9.81 m/s² = a (negative as it is going up)

Equation of motion

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-2.8^2}{2\times -9.81}\\\Rightarrow s=0.39959\ m

The height to which the apple above the point of release will reach is 0.39959 m

From the ground the distance will be 1.3+0.39959 = 1.69959 m

Distance from the tree house = 5.9-1.69959 = 4.20041 m

No, the apple will reach 4.20041 m below the tree house.

The values in the option do not reflect the answer.

5 0
2 years ago
According to the diagram, in order for a solar eclipse to occur, the Earth, Moon, and Sun must A) form a right angle with the Mo
torisob [31]

Answer:

B) form a straight line with the Moon in the middle.

Explanation:

  • For the occurrence of a solar eclipse the earth and the moon and the sun must be in a straight line and moon should be in center of the earth so that it completely blocks the rays of the sun and the shadow falls on earth and the sun appears to form a ring and thus the eclipse takes place.
7 0
2 years ago
Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless sur
d1i1m1o1n [39]

Answer:

The speed of bullet and wooden bock coupled together, V = 22.22 m/s

Explanation:

Given that,

Mass of the bullet, m = 0.04 Kg

Mass of the wooden block, M = 0.5 Kg

The initial velocity of the bullet, u = 300 m/s

The initial velocity of the wooden block, U = 0 m/s

The final velocity of the bullet and wooden bock coupled together, V = 0 m/s

According to the conservation of linear momentum, the total momentum of the body after impact is equal to the total momentum before impact.

Therefore,

                              mV + MV = mu + MU

                               V(m+M) = mu

                                 V = mu/(m+M)

Substituting the values in the above equation,

                                V = 0.04 Kg x 300 m/s  / (0.04 Kg+ 0.5 Kg)

                                    = 22.22 m/s

Hence, the speed of bullet and wooden bock coupled together, V = 22.22 m/s

8 0
2 years ago
"You have been asked to design a "ballistic spring system" to measure the speed of bullets. A spring whose spring constant is k
e-lub [12.9K]

Answer:

In your question which ask to design a ballistic spring system to measure the speed of bullet. The ask is to find the expression for the bullets speed by using the term given in your question so base on the data you have given and with my calculation the answer is  (M+m)*g*d + 1/2*k*(d1-d)^2

4 0
2 years ago
A charge Q is distributed uniformly along the x axis from x1 to x2. What would be the magnitude of the electric field at x0 on t
Lena [83]

Answer:

  E =  k Q    1 / (x₀-x₂) (x₀-x₁)

Explanation:

The electric field is given by

              dE = k dq / r²

In this case as we have a continuous load distribution we can use the concept of linear density

              λ= Q / x = dq / dx

              dq = λ dx

We substitute in the equation

           ∫ dE = k ∫ λ dx / x²

We integrate

           E = k λ (-1 / x)

We evaluate between the lower limits x = x₀- x₂ and higher x = x₀-x₁

           E = k λ (-1 / x₀-x₁ + 1 / x₀-x₂)

           E = k λ  (x₂ -x₁) / (x₀-x₂) (x₀-x₁)

We replace the density

             E = k (Q / (x₂-x₁)) [(x₂-x₁) / (x₀-x₂) (x₀-x₁)]

             E =  k Q    1 / (x₀-x₂) (x₀-x₁)

8 0
2 years ago
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