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OverLord2011 [107]
2 years ago
4

shani poses as the statue of liberty for an art class. she holds a torch above her head with her right hand and a book against h

er side with her left hand. she holds the pose for ten minutes. at the end of the session, she mentions to her friend that it was a lot of work to pose and that her arms are really tired. which describes the work shani did while she posed?
Chemistry
2 answers:
Igoryamba2 years ago
5 0
In this situation, Shani did not had any work done. It is because she did not moved from one place to another by maintaining her stationary position. Work done is equal to the force exerted multiplied to the distance traveled.
topjm [15]2 years ago
5 0

Answer:

She did no work while she posed because she did not move the torch or the book.

Explanation:

For the physics normal laws, work is given by the formula:

W=F*D

Where W represents work, F-Force and D-Distance.

For physics in order for there to be work there has to be a force applied in a certain distance, since she didn´t move the torch nor the book, she didn´t perform any job.

You might be interested in
Consider a saturated solution formed when 17.5 g of a solute dissolve in 28.3 g of a solvent, giving a total solution volume of
STALIN [3.7K]

Answer:

a) 38.2 % mass

b) 61.8 g solute/100 g solvent

c) 1.65 g/mL

Explanation:

Given the data:

mass of solute = 17.5 g

mass of solvent= 28.3 g

total solution volume= 27.8 mL

a)- mass percent= mass of solute/mass of solution x 100

mass of solution = mass solute + mass solvent = 17.5 g + 28.3 g = 45.8 g

mass % = 17.5 g/45.8 g x 100 = 38.2 % mass

b)- solubility = grams of solute/ 100 g solvent

                    = 17.5 g x (100 g /28.3 g solvent) = 61.8 g solute/100 g solvent  

c)- density = massof solution/total volumesolution  = 45.8 g/27.8 mL = 1.65 g/mL

7 0
2 years ago
How many grams of NH3 can be prepared from the synthesis of 77.3 grams of nitrogen and 14.2 grams of hydrogen gas?
lbvjy [14]

Answer:

80.41 g

Explanation:

Data Given:

Mass of Nitrogen (N₂) = 77.3 g

Mass of Hydrogen (H₂) = 14.2 g

many grams of NH₃ = ?

Solution:

First we look at the balanced synthesis reaction

              N₂   +    3 H₂  ------—> 2 NH₃

             1 mol      3 mol

As 1 mole of Nitrogen react with 3 mole of hydrogen

Convert moles to mass

molar mass of N₂ = 2(14) = 28 g/mol

molar mass of H₂ = 2(1) + 2 g/mol

Now

                     N₂             +           3 H₂        ------—>      2 NH₃

             1 mol (28 g/mol)     3 mol(2g/mol)

                    28 g                        6 g

28 grams of N₂ react with 6 g of H₂  

So

if 28 grams of N₂ produces 6 g of H₂  so how many grams of N₂ will react with 14.2 g of H₂.

Apply Unity Formula

                 28 g of N₂ ≅ 6 g of H₂

                 X g of N₂ ≅ 14.2 g of H₂

Do cross multiply

                X g of N₂ = 28 g x 14.2 g / 6 g

                X g of N₂ = 66.3 g

As we have given with 77. 3 g of N₂ but from this calculation we come to know that 66.3 g will react with 14.2 g of hydrogen and the remaining 10 g N₂ will be in excess

So, Hydrogen is limiting reactant in this reaction and the amount of NH₃ depends on the amount of hydrogen.

Now

To find mass of NH₃ we will do following calculation

Look at the reaction

As we Know

                     N₂             +           3 H₂        ------—>      2 NH₃

                                                   6 g                            2 mol

So, 6 g of hydrogen gives 2 moles of NH₃, then how many moles of NH₃ will be produce by 14.2 g

Apply Unity Formula

                 6 g of H₂ ≅ 2 mol of NH₃

                14.2 g of H₂ ≅ X mol of NH₃

Do cross multiply

               X mol of NH₃= 14.2 g x 2 mol / 6 g

                X mol of NH₃ = 4.73 mol

So, 14.2 g of hydrogen gives 4.73 moles of NH₃

Now

Convert moles of NH₃ to mass

Formula will be used

        mass in grams = no. of moles x molar mass . . . . . . (2)

Molar mass of  NH₃

Molar mass of  NH₃ = 14 + 3(1)

Molar mass of  NH₃ = 14 + 3 = 17 g/mol

Put values in equation 2

        mass in grams = 4.73 mole x 17 g/mol

        mass in grams =  80.41 g

mass of NH₃=  80.41 g

3 0
2 years ago
A gas has a mass of 3.82 g and occupies a volume of 0.854 L. The temperature in the laboratory is 302 K, and the air pressure is
4vir4ik [10]

m = given mass of gas = 3.82 g

M = molar mass of gas = ?

T = temperature of laboratory = 302 K

P = air pressure = 1.04 atm = 1.04 x 101325 pa

V = volume of gas = 0.854 L = 0.854 x 10⁻³ m³

using the ideal gas equation

PV = (m/M) RT

inserting the above values

(1.04 x 101325) (0.854 x 10⁻³) = (3.82/M) (8.314) (302)

M = 106.6 g

hence the molar mass of the gas comes out to be 106.6 g

3 0
2 years ago
Molecules containing a large number of hydroxyl groups are
alexandr402 [8]
Molecules containing a large number of hydroxyl groups are soluble in water. Molecules which contains the functional group hydroxyl or -OH are called alcohols. Water and alcohols share some similar properties. One would be its polar properties. Alcohols are polar molecules as they contain a partial positive and partial negative end. Making them to be miscible in water. The hydroxyl groups in alcohol are capable of forming hydrogen bonds with the water molecules and with other alcohols.  As the number of the hydroxyl groups increases, the polarity of the molecule would also increase making it more soluble in water.
6 0
2 years ago
The energy released in the fission of a 235u nucleus is about 200 mev. how much rest mass (in kg) is converted to energy in this
Liula [17]
 1kg = 1000grams 
<span>mass of uranium = 235
number of atoms in 1 mole = avogadro's number = 6.02 x 10</span>²³
<span>Each nucleus will release = 200 Mev of energy. 
So, E = 200 x (1000/235) x  6.02 x 10</span>²³
 = 5.12 x 10²⁶<span> Mev 
Now convert this to joules
1Mev = 1.60218 x 10</span>⁻¹³
5.12 x 10²⁶ Mev = 5.12 x 10²⁶ Mev  x 1.60218 x 10⁻¹³
= 8.21 x 10¹³ Joules
8 0
2 years ago
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