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kenny6666 [7]
2 years ago
9

Jeff puts on a leather jacket over his sweater. The sweater becomes negatively charged. Which statements about Jeff’s situation

are true? a. The sweater has a tendency to attract electrons. b. The sweater has a tendency to attract protons. c. The leather jacket has a tendency to attract electrons. d. The leather jacket has a tendency to attract protons. e. The leather jacket has a lower tendency to attract electrons than the sweater.
Physics
2 answers:
nikdorinn [45]2 years ago
8 0

b. The sweater has a tendency to attract protons.

exis [7]2 years ago
4 0

Answer:

The answer is A. The sweater has a tendency to attract electrons.

Explanation:

Taking into account the flow of electric charge, it is understood that when a body comes into contact with another and passes its electrons to it; The body that loses electrons is positively charged, while the body that gains or receives electrons is negatively charged. So it is concluded that the sweater is receiving electrons from the jacket.

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A plane traveling north at 100.0 km/h through the air gets caught in a 40.0 km/h crosswind blowing west. This turbulence caused
mojhsa [17]

Answer:

Explanation:

If I assume that the wind did not cause the plane to chage its velocity.

The plane will have a velocity of vp =  (0*i + 100*j) km/h relative to ground

The cart has a velocity of vc = (0*i - 20*j) km/h relative to the plane

vc' = vc + vp

vc' = (0*i + 100*j) + (0*i - 20*j) = (0*i + 80*j) km/h relative to the ground.

If I assume that the wind move the plane:

The plane will have a velocity of vp =  (-40*i + 100*j) km/h relative to ground

The cart has a velocity of vc = (0*i - 20*j) km/h relative to the plane

vc' = vc + vp

vc' = (-40*i + 100*j) + (0*i - 20*j) = (-40*i + 80*j) km/h relative to the ground.

In reality the wind would move the plane a little, not to the full speed of the wind, somewhere between these two values, but without more data it cannot be calculated.

6 0
2 years ago
Julius competes in the hammer throw event. The hammer has a mass of 7.26 kg and is 1.215 m long. What is the centripetal force o
nevsk [136]
In the circular motion of the hammer, the centripetal force is given by
F=m \frac{v^2}{r}
where m is the mass of the hammer, v its tangential speed and r is the distance from the center of the motion, i.e. the length of the hammer.
Using the data of the problem, we find:
F=m \frac{v^2}{r}=(7.26 kg) \frac{(31.95 m/s)^2}{1.215 m}=6100 N
4 0
2 years ago
Read 2 more answers
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
2 years ago
A person drops a stone down a well and hears the echo 8.9 s later. if it takes 0.9 s for the echo to travel up the well, approxi
Temka [501]

Total time in between the dropping of the stone and hearing of the echo = 8.9 s

Time taken by the sound to reach the person = 0.9 s

Time taken by the stone to reach the bottom of the well = 8.9 - 0.9 = 8 seconds

Initial speed (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s^2

Time taken (t) = 8 seconds

Let the depth of the well be h.

Using the second equation of motion:

h = ut + \frac{1}{2}\times a \times t^2

h = 0 \times 8 + \frac{1}{2} \times 9.8 \times 8^2

h = 313.6 m

Hence, the depth of the well is 313.6 m

4 0
2 years ago
In an experiment you are performing, your lab partner has measured the distance a cart has traveled: 28.4inch. You need the dist
alexgriva [62]

As per the question the distance travelled by  a car is 28.4 inch.

we are asked to determine the  conversion factor in centimeter  which when multiplied with 28.4 inch will give a unit.

we know that one inch =2.54 centimeter.

Hence 28.4 inch = 2.54  ×28.4 cm

                            =72.136 cm.

Now we have to determine the conversion factor .The multiplication factor is calculated as    P =\frac{28.4 inch*2.54cm}{1 inch}

                         p= 72.136 cm        [p is the multiplication factor.]

Hence the multiplication factor is 72.137 cm which will give unit conversion when multiplied with 28.4 inch.

                 

                             


4 0
2 years ago
Read 2 more answers
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