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Dovator [93]
2 years ago
8

The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting

on top of a 350-m hill? J How many times more gravitational potential energy would the same lander have on top of a 350-m hill on Earth? It would have times more gravitational potential energy.
Physics
2 answers:
Fittoniya [83]2 years ago
7 0

Answer:

672,000

6

Explanation:

I just did the assignment

faltersainse [42]2 years ago
5 0

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The equation for gravitational potential energy is GPE = mgh. 


GPE = 1200(1.6)(350) = 672000 J


Hope this answers the question. Have a nice day.

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Para proteger un computador de sobrecargas eléctricas, Juan coloca un filamento delgado de cobre llamado fusible en su circuito,
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Answer:

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Una vez el filamento se rompe, la corriente ya no puede circular por el (podes pensar en esta situación como un cable roto, la electricidad no puede circular por este cable)

Entonces, al romperse el filamento, en caso de una sobrecarga eléctrica, el flujo de electricidad se corta, y de esta forma se protege al computador de posibles sobrecargas.

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2 years ago
Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a
Anton [14]

Answer:

Explanation:

moment of inertia of each blade which is similar to rod rotating about its one end

= 1/3 ml²

moment of inertia of 3 blades = ml²

= 5500 x 46²

I = 11638 x 10³ kg m²

angular velocity = 2πn where n is rotation per second

n = 11 / 60

angular velocity = 2π x 11/60

= 1.1513 rad /s

angular momentum

= moment of inertia x angular velocity

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4 0
2 years ago
A thin partition divides a thermally insulated vessel into a lower compartment of volume V and an upper compartment of volume 2V
Anni [7]

Answer:

1.89mol

Explanation:

The entropy change during free expansion is express as

S_{f}-S_{i}=nRln(\frac{V_{F}}{V_{I}})\\

Where S is the entropy of the system,

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             R is the gas constant = 8.314 and

           V is the volume occupied at the initial and final stage

since the process is n adiabatic free expansion, the entropy of the system is constant. Hence we can re-write the equation as

S=nRln(\frac{V_{F}}{V_{I}})\\

where the  V_{i}=v\\ and V_{f}=2v+v=3v\\

S=17.28J/k\\ and

R=8.314\\

Now if we substitute in values we arrive at

17.28=(8.314)n*ln(\frac{3v}{v} )\\17.28=(8.314)n*ln(3 )\\17.28=(8.314)n*1.0986\\n=\frac{17.28}{8.314*1.0989}\\n=1.89 mole\\

6 0
2 years ago
Exercise provides a healthy outlet for feelings, which helps improve __________. A. emotional health B. mental health C. spiritu
Juliette [100K]

Answer: Option (A) is the correct answer.

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5 0
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Answer:

See the attached image and the explanation below

Explanation:

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These free body diagrams can be seen in the attached image.

First we perform a sum of forces on the x & y axes before cutting the cord, to be able to find the T tension of the wire. (This analysis can be seen in the attached image).

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Finally with equations 1 and 2 we can find the K ratio.

5 0
2 years ago
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