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astraxan [27]
2 years ago
14

A hobby rocket reaches a height of 72.3 meters and lands 111 meters from the launch point

Physics
1 answer:
faust18 [17]2 years ago
8 0
Using the following formulas for projectile motion:

Height, H = ( Vo^2 * sin theta^2 )/g

Range, R = ( Vo^2 * sin 2*theta )/g

Rearranging in terms of Vo^2:

Vo^2 = gH / sin theta^2

Vo^2 = gR / sin 2*theta

Equating the two formulas to each other to solve for the angle theta:

gR / sin 2*theta = <span>gH / sin theta^2
</span>
Substituting the given values:

(9.8)(111) / sin 2*theta = (9.8)(72.3)<span> / sin theta^2
</span>angle = 52.36 degrees

Therefore, the angle of launch is approximately 52.36 degrees.
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At one point in the rescue operation, breakdown vehicle A is exerting a force of 4000 N and breakdown vehicle B is exerting a fo
lukranit [14]

Answer:

1.) Magnitude = 5596 N

2.) Direction = 60 degrees

Explanation: You are given that the breakdown vehicle A is exerting a force of 4000 N at angle 45 degree to the vertical and breakdown vehicle B is exerting a force of 2000 N

Let us resolve the two forces into X and Y component

Sum of the forces in the X - component will be 4000 × cos 45 = 2828.43 N

Sum of the forces in the Y - component will be 2000 + ( 4000 × sin 45 )

= 2000 + 2828.43

= 4828.43 N

The resultant force R will be

R = sqrt ( X^2 + Y^2 )

Substitutes the forces at X component and Y component into the formula

R = sqrt ( 2828.43^2 + 4828.43^2 )

R = sqrt ( 31313752.53 )

R = 5595.87 N

The direction will be

Tan Ø = Y/X

Substitute Y and X into the formula

Tan Ø = 4828.43 / 2828.43

Tan Ø = 1.707106

Ø = tan^-1( 1.707106 )

Ø = 59.64 degree

Therefore, approximately, the magnitude and direction of the resultant force on the truck are 5596 N and 60 degree respectively.

8 0
2 years ago
The planets how and block are near each other in the Dorgon system. the Dorgons have very advanced technology, and a Dorgon scie
BlackZzzverrR [31]

Answer:

Decreasing the distance between Hox and Blox, increasing the mass of Hox, or increasing the mass of Hox and Blox.

Explanation:

The gravity force is directly proportional to the mass of the bodies and inversely proportional to the square of the distance that separates them.

Or

If we decrease the distance between both planets (Hox and Blox), the gravitational pull between them will increase.  

On the other hand, if we keep the distance between Hox and Blox, but we increase the mass of one of them, or increase the mass of both, the gravitational pull between them will also increase.

4 0
2 years ago
13. A hiker walks 200 m west and then walks 100 m north. In what direction is her resulting displacement?
prohojiy [21]
100m north west   is the answer                                      
4 0
2 years ago
Read 2 more answers
If you are lying down and stand up quickly, you can get dizzy or feel faint. This is because the blood vessels don't have time t
sammy [17]

Complete Question

If you are lying down and stand up quickly, you can get dizzy or feel faint. This is because the blood vessels don’t have time to expand to compensate for the blood pressure drop. If your brain is 0.4 m higher than your heart when you are standing, how much lower is your blood pressure at your brain than it is at your heart? The density of blood plasma is about 1025 kg/m3 and a typical maximum (systolic) pressure of the blood at the heart is 120 mm of Hg (= 0.16 atm = 16 kP = 1.6 × 104 N/m2).

Answer:

The pressure at the brain is P_b  = 89.872 \ mm \ of \ Hg

Explanation:

Generally is mathematically denoted as

                  P = \rho gh

Substituting 1025 kg/m^3 for \rho(the  density) , 9.8 m/s^2 for g (acceleration due to gravity) , 0.4m for h (the height )

We have that the pressure difference between the heart and the brain is

              P = 1025 * 9.8 *0.4

                  = 4018 N/m^2

But the pressure of blood at the heart is given as

               P_h=120 mm of Hg = 120 * 133 =  1.59*10^3Pa

Now the pressure at the brain is mathematically evaluated as

                 P_b = P_h - P

                     = 1.596*10^4 - 4018

                     = 11982 N/m^2

                      P_b= \frac{11982}{133} = 89.872 \ mm \ of \ Hg

   

     

3 0
2 years ago
A 5-ft-tall person walks away from the wall at a rate of 2 ft/sec. A spotlight is located on the ground 40 ft from the wall. How
AveGali [126]

Answer:

The rate of change of the height is - 4 ft/s

Solution:

As per the question:

Height of the person, y = 5 ft

The rate at which the person walks away, \frac{dx}{dt} = 4\ ft/s

Distance of the spotlight from the wall, x = 40 ft

Now,

To calculate the rate of change in the height, \frac{dy}{dt} of the person when, x = 10 m:

From fig 1.

\Delta ABC[\tex] ≈ [tex]\Delta PQC[\tex]Thus[tex]\frac{BC}{AB} = \frac{PQ}{QC}

\frac{y}{40} = \frac{5}{x}

xy = 200                                                                       (1)

Differentiating the above eqn w.r.t time t:

x\frac{dy}{dt} + y\frac{dx}{dt} = 0

Thus

\frac{dy}{dt} = - \frac{y}{x}\frac{dx}{dt}              (2)

From eqn (1):

When x = 10 ft

10y = 200

y = 20 ft

Using eqn (2):

\frac{dy}{dt} = - \frac{20}{10}\times 2 = - 4\ ft

8 0
2 years ago
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