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2 years ago

A 2.50 cm cube of copper metal has a mass of 140.125g.what is the density of copper

Chemistry

1 answer:

Nat2105 [25]2 years ago

6 0

We know that density = mass / volume

Volume of a cube = a^3

Where a= length of a side

Given :

edge length of cube = 2.50 cm

so volume of cube of copper = 2.50 X 2.50 X 2.50 = 15.625 cm^3

mass of copper = 140.125 g

So density = Mass / Volume = 140.125 / 15.625 = 8.968 g / cm^3

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You have a mixture that contains 0.380 moles of Ne(g), 0.250 moles of He(g), and 0.500 moles CH4(g) at 400 K and 7.25 atm. What

boyakko [2]

I think it is the pacific ocean

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2 years ago

Select the statement(s) that explain(s) the relationship between the arrangement of elements by size and first ionization energy

kow [346]

c. A full s subshell is able to shield a newly filled p subshell from the nucleus, making the first electron in a p subshell easy to remove.

Explanation:

From the given options, a full s-sublevel is able to shield a newly filled p-subshell from the nucleus thereby making the first electron in a p-subshell easy to remove is correct.

What is ionization energy?

Ionization energy is a measure of the readiness of an atom to lose an electron.

First ionization energy is the energy required to remove the most loosely held electron in the gas phase.

The size of an atom/element depends on the number of electrons it contains. The more the electrons, the larger its size.

The larger an atom becomes the lesser the ionization energy needed to remove the first electron from its outermost shell.

Electron - electron repulsion occurs when two electrons in the same sub-level repels one another.

Shielding effect is the ability of the inner electrons to protect the outer electrons from the pull of the nuclear charge.

In option C, a s-subshell has a greater shielding effect than the p,d and f sub-shell in that order.

A newly introduced electron in the p-sublevel will be loosely held and easier to remove.

Learn more:

First ionization energy brainly.com/question/2153804

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8 0

2 years ago

Read 2 more answers

CuSO4(aq) + 2NaOH(aq) Cu(OH)2(s) + Na2SO4(aq)

REY [17]

Your answer is right.

Important elements to consider:

- to use the balanced equation (which you did)
- divide the masses of each compound by the correspondant molar masses (which you did)
- compare the theoretical proportions with the current proportions

Theoretical: 2 mol of Na OH : 1 mol of CuSO4
Then 4 mol of NaOH need 2 mol of CUSO4.

Given that you have more than 2 mol of of CUSO4 you have plenty of it and the NaOH will consume first, being this the limiting reagent.

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2 years ago

Which formula represents the compound commonly known as phosphine PH PH2 PH3 PH4

AveGali [126]

The answer is C). PH3

4 0

2 years ago

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How many moles of alanine, C3H7NO2, are there in 159 g of alanine?How many moles of alanine, C3H7NO2, are there in 159 g of alan

Vanyuwa [196]

To find the number of moles of Alanine, we first need to find its molar mass

Finding the Molar mass:

To our convenience, we are already given the chemical formula of Alanine

Chemical formula: C₃H₇NO₂

Now, we will use this formula to find the molar mass of Alanine

to do that, we will replace the chemical symbols of elements with their respective molar masses and add them together

We know the following molar masses:

C is 12 g/mol

H is 1 g/mol

N is 14 g/mol

O is 16 g/mol

Now, we will replace the chemical symbols with their molar mass and will be multiplied by their values in subscript

C₃H₇NO₂

Molar mass = (12)*3 + (1)*7 + (14)*1 + (16)*2

Molar mass = 36 + 7 + 14 + 32

Molar mass = 89 grams/mol

Number of moles of Alanine in a 159 gram sample:

Number of moles = Given mass / Molar mass

Number of moles = 159 / 89

Number of Moles = 1.78 moles

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2 years ago