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sleet_krkn [62]
2 years ago
7

The tip of a tuning fork goes through 440 complete vibrations in a time of 0.510s. Find the angular frequency and the period of

the motion.
Physics
2 answers:
Stels [109]2 years ago
8 0
44 complete vibrations in 0.510s.

1 complete vibration would be in:   0.510/44 = 0.01159 s.

Hence the Period, T = 0.01159 s

Frequency, f = 1/T = 1/0.01159 ≈ 86.28 Hz

Angular frequency, ω = 2πf = <span>2π*86.28 </span>≈ 542.11 rad/s
Brilliant_brown [7]2 years ago
7 0
Solve for the time it will take to complete a revolution. That is,
                                   0.510 s / 440 revolutions = 51/44000 s
The frequency in Hertz is the reciprocal of this value thus the frequency is approximately equal to 862.75 Hz. 

Angular velocity expressed in radians/second
                          (440 rev / 0.510 s) x (2π rad / 1 rev) = 5420.787 rad/s

The period is the reciprocal of frequency which is approximately equal to 1.16x10^-3 s.

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Question 8 (4 points)
katrin2010 [14]

Answer:

The answer to your question is:

Explanation:

Data

Duane                                          Albert

d = 5 m ;  v = 3 m/s                     v = 4.2 m/s

a)                                                b)

Duane's                                      Albert's

d = 5 + (3)t                                  d = 4.2t

d = 5 + 3t

c)                            5 + 3t = 4.2t

                              4.2t - 3t = 5

                                      1.2t = 5

                                           t = 4.17 s

d)

Duane's

d= 5 + 3(4.17)

d = 17.51 m

Alberts

d = 4.2(4.17)

d = 17.51 m

4 0
2 years ago
Read 2 more answers
A runner has a momentum of 720 kg m/s and is traveling at a velocity of 5 m/s. What is his mass?
antiseptic1488 [7]
I could be wrong, but I'm pretty sure it's 144kg.
8 0
2 years ago
Read 2 more answers
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was s
exis [7]

Answer

given,

Mass of Kara's car = 1300 Kg

moving with speed = 11 m/s

time taken to stop = 0.14 s

final velocity = 0 m/s

distance between Lisa ford and Kara's car = 30 m

a) change in momentum of Kara's car

  Δ P = m Δ v                  

  \Delta P = m (v_f-v_i)

  \Delta P = 1300 (0 - 11)

  Δ P = - 1.43 x 10⁴ kg.m/s

b) impulse is equal to change in momentum of the car

    I = - 1.43 x 10⁴ kg.m/s

c) magnitude of force experienced by Kara

  I = F x t

 I is impulse acting on the car

 t is time

  - 1.43 x 10⁴= F x 0.14

    F = -1.021 x 10⁵ N

negative sign represents the direction of force

8 0
2 years ago
Read 2 more answers
If one of the satellites is at a distance of 20,000 km from you, what percent accuracy in the distance is required if we desire
Lesechka [4]
<span>It is quite straightforward to convert an uncertainty to a percent uncertainty. We can divide the amount of uncertainty by the original amount and then multiply by 100%.

(2 m / 20,000,000 m) X 100% = 0.00001%

The percent uncertainty is 0.00001%.

The percent accuracy is the 100% - percent uncertainty.
The percent accuracy = 100% - 0.00001% = 99.99999%

The percent accuracy is 99.99999%.</span>
8 0
2 years ago
A 2 kg stone is tied to a 0.5 m string and swung around a circle at a constant angular velocity of 12 rad/s. the angular momentu
Illusion [34]
Starting from the angular velocity, we can calculate the tangential velocity of the stone:
v=\omega r= (12 rad/s)(0.5 m)= 6 m/s

Then we can calculate the angular momentum of the stone about the center of the circle, given by
L=mvr
where
m is the stone mass
v its tangential velocity
r is the radius of the circle, that corresponds to the length of the string.

Substituting the data of the problem, we find
L=(2 kg)(6 m/s)(0.5 m)=6 kg m^2 s^{-1}
3 0
2 years ago
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