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LenKa [72]
1 year ago
12

What is the momentum of a 533 kg blimp moving east at +75 m/s

Physics
1 answer:
mylen [45]1 year ago
7 0

Answer:

39975kgm/s due east

Explanation:

Given parameters:

Mass of the blimp  = 533kg

Velocity  = +75m/s due east

Unknown:

Momentum of the body  = ?

Solution:

The momentum of a body is the amount of motion it posses.

 Momentum is the product of mass and velocity;

 

  Momentum = mass x velocity

  Insert the parameters and solve;

    Momentum  = 533 x 75  = 39975kgm/s

The momentum of the body is 39975kgm/s due east

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The reading on the scale is the tension on the string that connects the two objecst. In order to support the blocks it must pull the weights by a force magnitude of W. So, the tension of the rope is W. Therefore, the reading on the scale is W, D.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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west 1100 km / hr    ..

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What is the y component of a vector defined as 12.2m at 81.5°?
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Answer:

Explanation:

This is a displacement vector since it is defined in terms of distance (meters, to be exact). The way you find the y-component is

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V_y=12.2sin(81.5) and get

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3 0
2 years ago
Suppose a plot of inverse wavelength vs frequency has slope equal to 0.119, what is the speed of sound traveling in the tube to
strojnjashka [21]

Answer:

8.40 m/s

Explanation:

Slope of the plot is 0.119

Slope of a plot is given by the change in y direction divided by the change in x direction

Here, the y axis represents inverse wavelength and the x axis represents frequency.

f = Frequency (Hz, assumed)

v = Phase velocity (m/s, assumed)

λ = Wavelength (m, assumed)

So, slope

m=\frac{\frac{1}{\lambda}}{f}

Now,

\lambda=\frac{v}{f}\\\Rightarrow \lambda^{-1}=\frac{f}{v}

\\\Rightarrow m=\frac{\frac{f}{v}}{f}\\\Rightarrow 0.119=\frac{1}{v}\\\Rightarrow v=\frac{1}{0.119}\\\Rightarrow v=8.40\ m/s

The speed of sound travelling in the tube is 8.40 m/s

5 0
2 years ago
(a) A small object with mass 3.75 kg moves counterclockwise with constant speed 1.55 rad/s in a circle of radius 2.55 m centered
Eddi Din [679]

Answer:3.95 m/s

Explanation:

Given

mass of object m=3.75 kg

\omega =1.55 rad/s

radius of circle =2.55 m

initial Position r=2.55 \hat{i}

angular displacement \theta _0=8.95 rad

8.95 radian can be written as

1.42 (2\pi )

i.e. Particle is at first quadrant with \theta =0.4242\pi \times \frac{180}{\pi }

\theta =76.36^{\circ}

(c)velocity is v=\omgea \times r

v=1.55\times 2.55=3.95 m/s

8 0
2 years ago
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