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astraxan [27]
2 years ago
3

High voltage power lines transmit electrical energy at 240,000 V. Before the current reaches your home, the voltage is decreased

to the standard voltage for a wall socket. If a single step-down transformer is used, what is the ratio of turns in the primary coil to the secondary coil?
Physics
1 answer:
morpeh [17]2 years ago
4 0

Transformer is used to change the voltage from higher value to lower value

It is done by changing the number of coils in primary and secondary coils

The working equation is given as

\frac{V_s}{V_p} = \frac{N_s}{N_p}

here we have

V_s = Secondary coil voltage = 120 V

V_p = Primary coil voltage = 240,000 V

N_s = Turns in secondary coil

N_p = Turns in primary coil

Now by using the equation above

\frac{120}{240,000} = \frac{N_s}{N_p}

now we have

\frac{N_p}{N_s} = \frac{240,000}{120}

\frac{N_p}{N_s} = 2000

so the ratio must be 2000

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In this 2-dimensional graph, the x-component of each vector is the horizontal distance from the origin, while the y-component of each vector is the vertical distance from the origin. It can be seen that the c vector is 1 vertical unit away from the origin, which means that it has a y-component of 1.
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Which statements describe the characteristics of asteroids? Check all that apply. formed 4.6 billion years ago orbit the Sun bey
choli [55]

Answer:

formed 4.6 billion years ago

orbit the Sun

range in size from a few feet to more than 500 miles across

most are found in the asteroid belt

Explanation:

Asteroids are rocky bodies orbiting the sun. Asteroids are irregular is shape and size. The size varies from few feet to 500 miles across. Majority of the asteroids lie in asteroid belt which lies between the orbits of Mars and Jupiter. These are though to be remains of unformed planet about 4.6 billion years ago due to high gravitational pull of Jupiter. The largest asteroid is Ceres which is also a dwarf planet. The mass of the entire asteroid belt is just 4% the  mass of the moon.

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A box of mass 8 kg slides across a frictionless surface at an initial speed 1.5 m/s into a relaxed spring of spring constant 69
Sav [38]

Answer:

1.1 sec

Explanation:

m = mass of the box = 8 kg

k = spring constant of the spring = 69 N/m

v = initial speed of the box = 1.5 m/s

t = time period of oscillation of box in contact with the spring

Time period is given as

t = \pi \sqrt{\frac{m}{k}}

Inserting the values

t = (3.14) \sqrt{\frac{8}{69}}

t = 1.1 sec

5 0
2 years ago
A 92-kg skier is sliding down a ski slope that makes an angle of 30 degrees above the horizontal direction. The coefficient of k
9966 [12]

Answer:

a = 4.05 m/s²

Explanation:

Known data

m= 92 kg  : mass of the  skier

θ =30°  :angle θ of the ski slope  with respect to the horizontal direction

μk= 0.10 : coefficient of kinetic friction

g = 9.8 m/s² : acceleration due to gravity

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

We define the x-axis in the direction parallel to the movement of the block on the ramp and the y-axis in the direction perpendicular to it.

Forces acting on the skier

W: Weight of the skier : In vertical direction

N : Normal force : perpendicular to the ski slope

f : Friction force: parallel to the ski slope

Calculated of the W

W= m*g

W=  92kg* 9.8 m/s² = 901,6 N

x-y weight components

Wx= Wsin θ= 901,6 N *sin 30° = 450.8 N

Wy= Wcos θ = 901,6 N *cos 30° =780.8 N

Calculated of the N

We apply the formula (1)

∑Fy = m*ay    ay = 0

N - Wy = 0

N = Wy

N = 780.8 N

Calculated of the f

f = μk* N=  0.10*780.8 N  

f = 78.08 N

We apply the formula (1) to calculated acceleration of the skier:

∑Fx = m*ax  ,  ax= a  : acceleration of the block

Wx - f = m*a

450.8- 78.08 = ( 92)*a

372.72 =  (92)*a

a = (372.72)/ (92)

a = 4.05 m/s²

6 0
2 years ago
if a torque of 55.0 N/m is required and the largest force that can be exerted by you is 135 N what is th e length of the lever a
Whitepunk [10]

Answer:

r=0.41m

Explanation:

Torque is defined as the cross product between the position vector ( the lever arm vector connecting the origin to the point of force application) and the force vector.

\tau=r\times F

Due to the definition of cross product, the magnitude of the torque is given by:

\tau=rFsin\theta

Where \theta is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when sin\theta is equal to one, solving for r:

r=\frac{\tau}{F}\\r=\frac{55\frac{N}{m}}{135N}\\r=0.41m

7 0
2 years ago
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