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Mrac [35]
2 years ago
6

The following diagram shows resistors in ___ and is ____ of the arrangement of circuit elements in homes.

Physics
2 answers:
Fed [463]2 years ago
7 0

Electrical things in parallel are typical of circuit elements in homes.

Electrical things in series are not typical of circuit elements in homes.

Every electrical thing in a house is in parallel.  Sometimes they're also in parallel with the electrical devices in other houses nearby. 

ankoles [38]2 years ago
6 0
I wanna say that .....Electrical things in parallel are typical of circuit elements in homes.Electrical things in series are not typical of circuit elements in homes.Every electrical thing in a house is in parallel.  Sometimes they're also in parallel with the electrical devices in other houses nearby. 
not a 100% sure if that correct i hope so mark me the brainiest  if its right please :) 
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Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink?
bearhunter [10]

Answer:

It will sink

Explanation:

An object in the water can float only if its density is lower than the density of the water.

In fact, for an object completely immersed in water, there are two forces acting on it:

- Its weight, W=mg=\rho_o V g, downward, where \rho_o is the density of the object, V its volume and g the gravitational acceleration

- The buoyant force, B=\rho_w V g, upwards, there \rho_w is the density of the water

We see that when the density of an object is larger than the density of the water, \rho_o > \rho_w, the weight is greater than the buoyant force, W>B, so the object sinks.

In this case, the rock has a density of 1.73 g/cm3, while water has a density of 1.0 g/cm^3, so the rock will sink.


5 0
2 years ago
Read 2 more answers
Pressure and volume changes at a constant temperature can be calculated using
Crank
It can be calculated using Boyle's Law.  A.
3 0
2 years ago
The charged particles in the beams that Thomson studied came from atoms. As these particles moved away from their original atoms
aalyn [17]

The question to the above information is;

What is the best use of an atomic model to explain the charge of the particles in Thomson's beams?

Answer;

An atom's smaller negative particles are at a distance from the central positive particles, so the negative particles are easier to remove.

Explanation;

-Atoms are comprised of a nucleus consisting of protons (red) and neutrons (blue). The number of orbiting electrons is the same as the number of protons and is termed the "atomic number" of the element.

J.J. Thomson discovered the electron. Atoms are neutral overall, therefore in Thomson’s ‘plum pudding model’:

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5 0
2 years ago
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A 6-in-wide polyamide F-1 flat belt is used to connect a 2-in-diameter pulley to drive a larger pulley with an angular velocity
Likurg_2 [28]

Answer:

a) Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2  = 239.6 N,

b) Ha = 1863.75 N, nfs = 1 , length = 11.8 mm

Explanation:

Given that:

γ= 9.5 kN/m³ = 9500N/m3

b = 6 inches = 0.1524 m

t = 0.0013 mm

d = 2 inches  = 0.0508 m

n = 1750 rpm

H_{nom}=2hp=1491.4W

L = 9 ft = 2.7432 m

Ks = 1.25

g = 9.81 m/s²

a)

w=\gamma b t = 9500* 0.1524*0.0013=1.88N/m

V=\frac{\pi d n}{60} =\pi *0.0508*1750/60=4.65 m/s

F_c=\frac{wV^2}{g}=1.88*4.65^2/9.81=4.15N

(F_1)_a=bF_aC_pC_v=0.1524*6000*0.7*1=640N

T=\frac{H_{nom}n_dK_s}{2\pi n}= \frac{1491*1.25*1}{2*\pi*1750/60}=10.17Nm

F_2=(F_1)_a-\frac{2T}{D}= 640-\frac{2*10.17}{0.0508} =239.6N

F_i=\frac{(F_1)_a+F_2}{2} -F_c=435.65N

b)

H_a=1491*1.25=1863.75W

n_f_s=\frac{H_a}{H_{nom}K_S }=1

dip = \frac{L^2w}{8F_i} =\frac{2.7432*1.88}{435.65}=11.8mm

7 0
2 years ago
Hoosier Manufacturing operates a production shop that is designed to have the lowest unit production cost at an output rate of 1
abruzzese [7]

Answer:

90.77%

its capacity utilization rate for the month is 90.77%

Explanation:

The capacity utilisation rate can be expressed mathematically as;

Capacity utilisation rate = capacity used/Best operating level × 100%

Given;

Total Number of production time = 205hours

Production output/capacity used = 21400 units

Best operation rate = 115units/hour

Best operation output for the month of July( at best operation level )

=115units/hour × 205 hours = 23575 units

Capacity utilisation rate = 21400/23575 × 100%

= 90.77%

3 0
2 years ago
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