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2 years ago

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An object is traveling at a constant velocity of 15 m/s when it experiences a constant acceleration of 3.5 m/s2 for a time of 11

s. What will its velocity be after that acceleration?

1 answer:

Luda [366]2 years ago

7 0

Vf=Vi+at=15m/s+(3.5m/s^2)(11s)=53.5m/s

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In order to overcome an object’s inertia (resistance to change), it must be acted upon by an unbalanced force, so the answer to the problem is letter C.

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