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Sever21 [200]
2 years ago
3

Which situations show examples of work occurring? Check all that apply. A student carries a stack of books to the library. A sho

pping cart is pushed through a parking lot. A hockey puck slides on ice, with constant velocity. An airplane slows to a stop on a runway. A pool ball bounces off the edge of a pool table.
Physics
2 answers:
Aleonysh [2.5K]2 years ago
8 0

The correct answers are option: B, D and E or 2, 4 and 5

AfilCa [17]2 years ago
6 0

Answer:  

A student carries a stack of books to the library - No work done the force to carry the books is perpendicular to the displacement. Thus, work done = F s cos 90° = 0  

A shopping cart is pushed through a parking lot. - Work is done, as there is a force in the direction of the displacement of the cart.  

A hockey puck slides on ice, with constant velocity. -No work is done. As the hockey puck is mongol with constant velocity, it means there is no acceleration-thus, no unbalanced force acting. When F = 0, W =0.  

An airplane slows to a stop on a runway- negative work is done as the airplane is decelerating and moving on runway. When it stops, then there is no work being done but before that-yes.  

A pool ball bounces off the edge of a pool table- work done. When pool ball bounces of the edge, it free falls under gravity in the direction of the force. Thus, work is being done.  

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The point on the graph that lies on the y-axis (vertical axis) is called the y-intercept. What does the y-intercept tell you abo
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Answer:

The starting position of the runner.

Explanation:

When you look at the graph, you can see that the first point on the graph is twenty on the y-axis.

The runner starts at twenty, and ends at thirty.

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7 0
2 years ago
A negative charge of -0.550 μC exerts an upward 0.900-N force on an unknown charge that is located 0.300 m directly below the fi
allochka39001 [22]

Answer:

a.   q2 = 16.4μC, positive charge

b.   F = 0.900N

c.   downward

Explanation:

a. In order to calculate the charge of the unknown charge you use the following formula, for the electric force between two charges:

F_e=k\frac{q_1q_2}{r^2}            (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

r: distance between the charges = 0.300m

q1: charge 1 = -0.550 μC = 0.550*10^-6C

q2: charge 2 = ?

Fe: electric force = 0.900N

The force exerted in the second charge points upward, then, the sign of the second charge is positive because this charge is getting closer to the first one.

You solve the equation (1) for the second charge ans replace the values of the other parameters:

q_2=\frac{r^2F_e}{kq_1}=\frac{(0.300m)^2(0.900N)}{(8.98*10^9Nm^2/C^2)(0.550*10^{-6}C)}\\\\q_2=1.64*10^{-5}C\\\\q_2=16.4*10^{-6}C=16.4*10\mu C

The values of the second charge is 1.64 μC

b. By the third Newton Law, you have that the force exerted in the second charge is equal to the force exerted by the first charge on the second one.

The force exerted on the first charge is 0.900N

c. The charges are attracting between them, then, the force exerted on the first charge is pointing downward.

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2 years ago
Where is the steering nozzle located on a pwc?
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At the rear.

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3 0
2 years ago
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Find your mass if a scale on earth reads 650 N when you stand on it.
netineya [11]

Weight = (mass) x (gravity)

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The answer is 96 N .....................................
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2 years ago
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