answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alina1380 [7]
2 years ago
4

A damped harmonic oscillator loses 6.0% of its mechanical energy per cycle.

Physics
1 answer:
choli [55]2 years ago
8 0

1. The problem statement, all variables and given/known data

A damped harmonic oscillator loses 6.0% of it's mechanical energy per cycle. (a) By what percentage does it's frequency differ from the natural frequency f

0

=

(

1

2

π

)

√

k

m

? (b) After how many periods will the amplitude have decreased to  

1

e

of it's original value?

2. Relevant equations

natural frequency

f

0

=

(

1

2

π

)

√

k

m

damped frequency

f

′

=

1

2

π

√

k

m

−

b

2

4

m

2

displacement for lightly damped harmonic oscillator

x

=

A

e

(

−

b

2

m

)

t

c

o

s

ω

′

t

Total mechanical energy

E

=

1

2

k

A

2

=

1

2

m

v

2

m

a

x

And I know the mean half life,  

2

m

b

is the time until oscillations reach 1/e of original.

3. The attempt at a solution

I used the A^2 expression for E and the A decay term,  

A

e

(

−

b

2

m

)

t

,said it loses 6% of E when A^2 = .94A^2 (original) or in other words when

A

e

(

−

b

2

m

)

t

=  

√

0.94

A

so,  

e

(

−

b

2

m

)

t

=  

√

.94

−

b

2

m

t

=  

1

2

ln(.94)

t =  

− 1. The problem statement, all variables and given/known data

A damped harmonic oscillator loses 6.0% of it's mechanical energy per cycle. (a) By what percentage does it's frequency differ from the natural frequency f

0

=

(

1

2

π

)

√

k

m

? (b) After how many periods will the amplitude have decreased to  

1

e

of it's original value?

2. Relevant equations

natural frequency

f

0

=

(

1

2

π

)

√

k

m

damped frequency

f

′

=

1

2

π

√

k

m

−

b

2

4

m

2

displacement for lightly damped harmonic oscillator

x

=

A

e

(

−

b

2

m

)

t

c

o

s

ω

′

t

Total mechanical energy

E

=

1

2

k

A

2

=

1

2

m

v

2

m

a

x

And I know the mean half life,  

2

m

b

is the time until oscillations reach 1/e of original.

3. The attempt at a solution

I used the A^2 expression for E and the A decay term,  

A

e

(

−

b

2

m

)

t

,said it loses 6% of E when A^2 = .94A^2 (original) or in other words when

A

e

(

−

b

2

m

)

t

=  

√

0.94

A

so,  

e

(

−

b

2

m

)

t

=  

√

.94

−

b

2

m

t

=  

1

2

ln(.94)

t =  

−

m

b

ln(.94)  

But this is time and I need it to be one cycle so do I plug the period in for t?  

T = 1/f or 2∏ ω?

m

b

ln(.94)  

But this is time and I need it to be one cycle so do I plug the period in for t?  

T = 1/f or 2∏ ω?

You might be interested in
Capillary waves travel what than long waves
7nadin3 [17]
Faster than. Hope this helps!!!
6 0
2 years ago
Read 2 more answers
An owl has a mass of 4.00 kg. It dives to catch a mouse, losing 800.00 J of its GPE. What was the starting height of the owl, in
vesna_86 [32]

Answer:

height =20m

Explanation:

gpe=mgh

800=4×10×x

40x=800

x=20

3 0
2 years ago
Which law of motion accounts for the following statement? "When a marble and a billiard ball are impacted by the same force, the
Komok [63]
The second law explains this.
4 0
2 years ago
Read 2 more answers
A 1-kg mass is dropped from a third floor window. The acceleration of the mass is found to be 8 m/s2. What is the average force
Paha777 [63]
Summary:
m=1kg
a=8 m/s^2
g= 9,8 m/s^2
F(ar)=?


I hope to help you

7 0
2 years ago
A person who weighs 625 N is riding a 98-N mountain bike. Suppose that the entire weight of the rider and bike is supported equa
kozerog [31]

Answer:

A = 4.76 x 10⁻⁴ m²

Explanation:

given,                                  

weight of the person = 625 N

weight of the bike = 98 N        

Pressure on each Tyre = 7.60 x 10⁵ Pa

Area of contact on each Tyre = ?          

total weight of the system = 625 + 98

                                             = 723 N

Let F be the force on both the Tyre

F + F = W                                    

2 F  = 723                                    

F = 361.5 N                                

F = P A                                            

A = \dfrac{F}{P}                          

A = \dfrac{361.5}{7.60 \times 10^5}

A = 4.76 x 10⁻⁴ m²

7 0
2 years ago
Other questions:
  • What volume in milliliters will 0.00922 g of h2 gas occupy at stp?
    12·1 answer
  • A pendulum of 50 cm long consists of small ball of 2kg starts swinging down from height of 45cm at rest. the ball swings down an
    5·1 answer
  • For a sine wave depicting simple harmonic motion, the smaller the amplitude of the wave, the smaller the of the pendulum from th
    14·2 answers
  • postal worker on a bicycle travels at an average speed of 4m/s for 3 minutes. Work out how far she travelled.
    7·2 answers
  • Two identical loudspeakers that are 5.00 m apart and face toward each other are driven in phase by the same oscillator at a freq
    11·1 answer
  • A uniform 1.4-kg rod that is 0.75 m long is suspended at rest from the ceiling by two springs, one at each end of the rod. Both
    8·1 answer
  • Rod AB is held in place by the cord AC. Knowing that the tension in the cord is 1350 N and that c 5 360 mm, determine the moment
    11·1 answer
  • The total mechanical energy of a simple harmonic oscillating system is
    10·1 answer
  • cicadas produce a sound that has a frequency of 123 Hz. what is the wavelength of this sound in the air? the speed of sound in a
    15·1 answer
  • Isabella deja caer accidentalmente un bolígrafo desde su balcón mientras celebra que resolvió satisfactoriamente un problema de
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!