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2 years ago

3

sophia invested some money in a bank at a fixed rate of interest compounded annually. the equation below shows the value of her

investment after x years: f(x) = 500(1.05)x what was the average rate of change of the value of sophia's investment from the second year to the fourth year? 14.13 dollars per year 28.25 dollars per year 50.00 dollars per year 56.50 dollars per year

2 answers:

Anastaziya [24]2 years ago

5 0

Answer:

it is 28.25 dollars per year

Step-by-step explanation:

inessss [21]2 years ago

4 0

$f(2)=500(1.05)^{2}=$551.25$
$f(4)=500(1.05)^{4}=$607.75$
The change in value over 2 years = $607.75 - $551.25 = $56.50.
Therefore the average rate of change is $56.50 / 2 = $28.25 per year.
The second choice is correct.

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A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a

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a) 0.954

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Step-by-step explanation:

We are given the following information in the question:

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We are given that the distribution of particular interest rate is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

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$P(x \geq 3.8) = 1 - 0.046 = 0.954 = 95.4\%$

b) P(At most 8 percent)

$P(x \leq 8) = P(z \leq \displaystyle\frac{8-6}{1.3}) = P(z \leq 1.53)$

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2 years ago

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Given

One month julia collected 8.4 gallons of rainwater.

she used 5.2 gallons of rainwater to water her garden

6.5 gallons of rainwater to water flowers

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To proof

As given in the question

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Total water she used in the month = 5.2 gallons + 6.5gallons

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Answer:

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Step-by-step explanation:

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$SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}$

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In order to test the hypothesis the statistic is given by:

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