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solmaris [256]
2 years ago
9

What is the average speed of a cheetah that Sprint's 100m in 4 seconds How about if it sprints 50m in two seconds

Physics
2 answers:
Kay [80]2 years ago
8 0

Answer:

25m/s in both cases

Explanation:

The formula for the average speed is:

velocity=\frac{distance}{time}

For the first scenario distance is 100m and time is 4 seconds, the velocity is:

velocity =\frac{100m}{4s}=25m/s

For the second scenario the distance is 50m and the time is 2 seconds, so the velocity:

velocity=\frac{50m}{2s} =25m/s

The average speed is the sane for the two scenarios described.

Liono4ka [1.6K]2 years ago
6 0
Speed = distance/time

So for 1) 100m divided by 4 is 25 so the cheetah was travelling 25m/s

2) is the same concept: 50/2 = 25 so the cheetah was travelling at 25m/s
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d. 37 °C

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m_{m} = mass of lump of metal = 250 g

c_{m} = specific heat of lump of metal  = 0.25 cal/g°C

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c_{w} = specific heat of water = 1 cal/g°C

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m_{c} = mass of calorimeter  = 500 g

c_{c} = specific heat of calorimeter = 0.10 cal/g°C

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Using conservation of heat

Heat lost by lump of metal = heat gained by water + heat gained by calorimeter

m_{m} c_{m} (T_{mi} - T_{f}) = m_{w} c_{w} (T_{f} - T_{wi}) +  m_{c} c_{c} (T_{f} - T_{ci}) \\(250) (0.25) (70 - T_{f} ) = (75) (1) (T_{f} - 20) + (500) (0.10) (T_{f} - 20)\\T_{f} = 37 C

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Two balls with charges +Q and +4Q are separated by 3R. Where should you place another charged ball Q0 on the line between the tw
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As badminton court is usually slippery and flat with no or very little friction and while playing badminton, players have to move very fast from place to place.

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