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2 years ago

Draw a lewis structure for so2 in which all atoms obey the octet rule. show formal charges. do not consider ringed structures.

Chemistry

1 answer:

Aleonysh [2.5K]2 years ago

6 0

Formal charge = valence electron - bonds - dots.
double bonded oxygen = 6-2-
4 so it is 0
single bonded oxygen = 6-1-6 so it is -1
sulfur = 6-3-2 so it is +1

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Answer:

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Explanation:

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2 years ago

How many molecules are there in 345 grams of carbon dioxide?

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The graph shows a sample of gas when it is hot, cold, and at room temperature.

AveGali [126]

Answer:

B represents gas at room temperature and C represents hot gas.

Explanation:

As the temperature increases, the no. of particles that has higher energy increases.

So, A represents the cold gas, because it has the lowest no. of particles that has high energy.

B represents the gas at room T because it has more no. of particles with higher energy.

C represents the hot gas, because it is the curve that has the highest no. of particles with high energy.

So, the right choice is:

B represents gas at room temperature and C represents hot gas.

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2 years ago

Consider the following system at equilibrium where H° = -87.9 kJ, and Kc = 83.3, at 500 K. PCl3(g) + Cl2(g) PCl5(g) If the VOLUM

7nadin3 [17]

Answer:

The value of Kc C. remains the same.

The value of Qc C. is less than Kc.

The reaction must: A. run in the forward direction to reestablish equilibrium

The number of moles of Cl2 will B. decrease.

Explanation:

Le Chatelier's Principle states that if a system in equilibrium undergoes a change in conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.

A decrease in volume causes the system to evolve in the direction in which there is less volume, that is, where the number of gaseous moles is less.

But temperature is the only variable that, in addition to influencing equilibrium, modifies the value of the constant Kc. So if the volume of the equilibrium system is suddenly decreased at constant temperature: The value of Kc remains the same.

As mentioned, if the volume of an equilibrium gas system decreases, the system moves to where there are fewer moles. In this case, being:

PCl₃(g) + Cl₂(g) ⇔ PCl₅(g)

The equilibrium in this case then shifts to the right because there is 1 mole in the term on the right, compared to the two moles on the left. So, The reaction must: A. run in the forward direction to reestablish equilibrium.

By decreasing the volume, and so that Kc remains constant, being:

$Kc=\frac{[PCl_{5} ]}{[PCl_{3}]*[Cl_{2} ]}=\frac{\frac{nPCl_{5} }{Volume} }{\frac{nPCl_{3}}{Volume}*\frac{nCl_{2} }{Volume} } =\frac{nPCl_{5}}{nPCl_{3}*nCl_{2}} *Volume$

where nPCl₅, nPCl₃ and nCl₂ are the moles in equilibrium of PCl₅, PCl₃ and Cl₂

so, the number of moles of Cl₂ should decrease.The number of moles of Cl2 will B. decrease.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system will evolve to the right, the direct reaction prevailing, to increase the concentration of products. So in this case, if the reaction moves to the right, the value of Qc C. is less than Kc.

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2 years ago

Three measurements of 34.5m, 38.4m, and 35.3m are taken. If the accepted value of the measurement is 36.7m, what is the percent

8_murik_8 [283]

Answer:

Explanation:

% error in 1

36.7-34.5/36.7*100=5.99%

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38.4-36.7/36.7*100=4.63℅

% error in 3

36.7-35.3/36.7*100=3.81%

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2 years ago