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Vlad [161]
2 years ago
14

A block weighing 15 newtons is pulled to the top of an incline that is 0.20 meter above the ground, as shown below. if 4.0 joule

s of work are needed to pull the block the full length of the incline, how much work is done against friction?
Physics
1 answer:
Annette [7]2 years ago
3 0

Total work done here against two forces

1. Work done against gravity

2. work done against friction

Here work done against gravity is given by

W_g = mgH

here we know that weight of the block will be

Weight = mg = 15 N

H = 0.20 m

W_g = 15(0.20) = 3J

now we will say

W_{total} = W_{friction} + W_g

as we know that total work

W_{total} = 4J

4 = 3 + W_{friction}

W_{friction} = 4 - 3 = 1J

so work done against friction is 1 J

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Answer:

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Explanation:

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Therefore, for the horizontal component, we have:

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<em>b) Fv cosθ</em>

<em></em>

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<em></em>

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Answer:

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