Calculate the acceleration of the car for each set of conditions using the formula a = (v2 – v1) / (t2 – t1) where v2 and v1 are
2 answers:
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Answer:
A : A restoring force acts on an object in simple harmonic motion that is directed in the same direction as the object's displacement.
Explanation:
Statement A is the false one:
A : A restoring force acts on an object in simple harmonic motion that is directed in the same direction as the object's displacement. --> FALSE. The restoring force in the simple harmonic motion is given by
where
k is the spring constant
x is the displacement of the system, measured with respect to the equilibrium position
As we can notice from the equation, there is a negative sign in front of (kx): this means that the force, F, and the displacement, x, have opposite directions. In fact, the restoring force of a simple harmonic oscillator always acts to restore the equilibrium position, therefore it acts in the opposite direction as that of the displacement.
Answer:
1)H=714 Watts of energy is given out.
2)614.34 KCal energy is burnt in an hour in the room
3)In freezing conditions, 1337.09 KCal is spent in an hour.
Explanation:
The formula for thermal conductivity states that the rate of heat loss H is as follows:
H= where,
K=Coefficient of thermal conductivity
A=Area of Cross Section
H=Rate of heat loss
x=Thickness of the material
=Temperature difference between the two surfaces of the body in context
=37°C ie. Body Temperature
=20°C ie. Room Temperature
For first case, =17°C or 17°F
K for fat= 0.21
A=2
x=0.01 m
H=
H=714 Watts of energy is given out.
2) ×
Energy= 714 × 60 × 60=2570400 J
2570400 J=614.3403442 KCal
Therefore, 614.3403442 KCal energy is burnt in an hour.
3) Only the temperature difference becomes 37°C from 17°C , rest everything remains the same, therefore the energy will also vary due to the temperature factor and more energy will be spent as in freezing climate °C
E==1337.09 KCal
In freezing conditions, 1337.09 KCal is spent in an hour.