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Alex73 [517]
2 years ago
14

Calculate the acceleration of the car for each set of conditions using the formula a = (v2 – v1) / (t2 – t1) where v2 and v1 are

the first and second velocities and t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Acceleration is reported in m/s2. Record these accelerations, to two decimal places, in Table E. The acceleration for the car with one washer is m/s2. The acceleration for the car with two washers is m/s2. The acceleration for the car with three washers is m/s2. The acceleration for the car with four washers is m/s2.
Physics
2 answers:
Pavel [41]2 years ago
8 0

Answer:

               1.   0.19

              2.  0.33

              3.  0.47

              4.  0.62

Arisa [49]2 years ago
4 0

Answer:  1.  0.19

               2.  0.33

               3.  0.47

               4.  0.62

Explanation:  just did it & these are the correct answers

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A solenoid of length 0.700m having a circular cross-section of radius 5.00cm stores 6.00 μJ of energy when a 0.400-A current run
AURORKA [14]

Answer:

The winding density of the solenoid, n = 104 turns/m

Explanation:

Given that,

Length of the solenoid, l = 0.7 m

Radius of the circular cross section, r = 5 cm = 0.05 m

Energy stored in the solenoid, E=6\ \mu J=6\times 10^{-6}\ J

Current, I = 0.4 A

To find,

The  winding density of the solenoid.

Solution,

The expression for the energy stored in the solenoid is given by :

U=\dfrac{1}{2}LI^2

Where

L is the self inductance of the solenoid

L=\mu_on^2lA

n is the winding density of the solenoid

n=\sqrt{\dfrac{2U}{\mu_oI^2l\pi r^2}}

n=\sqrt{\dfrac{2\times 6\times 10^{-6}}{4\pi \times 10^{-7}\times 0.7\times (0.4)^2\pi (0.05)^2}}

n = 104 turns/m

So, the winding density of the solenoid is 104 turns/m

8 0
2 years ago
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A body A of mass 1.5kg, travelling along the positive x-axis with speed 4.5m/s, collides with another body B of mass 3.2kg which
Pie
Momentum before the collision
x-direction:
p = m₁v₁ = 1.5 * 4.5 = 6.75
x-direction:
p = 0

momentum after the collision is conserved:
x-direction:
p = 6.75 = m₁v₁ + m₂v₂ = 1.5 * 2. 1* cos -30° + 3.2 * v₂*cos θ
y-direction:
p = 0 = m₁v₁ + m₂v₂ = 1.5 * 2.1 * sin -30° + 3.2 * v₂ * sin θ

Solve the two equations for v₂ and θ.

5 0
2 years ago
Technician A says that the use of some RTV sealants to seal components on an engine can damage the oxygen sensor. Technician B s
netineya [11]

Answer: The correct option is C(both A and B)

Explanation:

In engine chambers, internal combustion of fuel is used to produce mechanical energy.

RTV ( Room Temperature Vulcanising) sealants are silicon products used for the sealing purpose of the engine component. As the name implies once exposed to air, it solidifies. However, it has a negative effect on the oxygen sensor of the engine components by makes a coating over the sensors with the silicone film and, after a time, will affect the operation performed by them. Therefore Technician A is correct.

Technician B is equally correct in that an engine need to be lubricated with oil to help cool the moving part while on. But in order to ensure that oil reaches all movable parts a common method know as heavy-duty reversible spin drills is applied. This method regulates the flow of oil using the engine.

7 0
2 years ago
An airplane is delivering food to a small island. It flies 100 m above the ground at a speed of 150 m/s .
miss Akunina [59]

Answer:

The airplane should release the parcel 6.7*10^2 m before reaching the island

Explanation:

The height of the plane is y_0=100m, and its speed is v=150 m/s

When an object moves horizontally in free air (no friction), the equation for the y measured with respect to ground is

y=y_0 - \frac{gt^2}{2}    [1]

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If we isolate t from the equation [1] and replace it in equation [2] we get

X = V . \sqrt{\frac{2y_0}{g}}

Using the given values:

x = 150 m/s  \sqrt{\frac{2\times 100m}{9.8 m/sec^2}}

x = 6.7*10^2 m

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neonofarm [45]
T o a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what is the man's velocity? it is 4m/s east
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