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2 years ago

What is the kinetic energy of a 26 kg eagle flying at an altitude of 65 m at a speed of 19 m/s?

Physics

1 answer:

sweet [91]2 years ago

4 0

Answer:

4693 J

Explanation:

The kinetic energy of the eagle is given by:

$K=\frac{1}{2}mv^2$

where

m is the mass of the eagle

v is the speed of the eagle

In this problem, m = 26 kg and v = 19 m/s. Substituting into the formula, we find

$K=\frac{1}{2}(26 kg)(19 m/s)^2=4693 J$

As we can see, the altitude of the eagle is not relevant for the calculation of the kinetic energy.

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Which pair of graphs represent the same motion of an object

ASHA 777 [7]

To be able to identify that the object is in the same motion, we should find the graphs that has an increasing slope of displacement and with the constant velocity with varying time. Graphs on letter D satisfies these requirements.

<em>ANSWER: D</em>

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2 years ago

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An ultrasound pulse has a wavelength of 1.0mm. Its speed in water is 1400m. What’s the frequency?

timama [110]

Answer:

$1.4\cdot 10^6 Hz$

Explanation:

The relationship between the frequency, the wavelength and the speed of a wave is given by the wave's equation:

$v=f \lambda$

where

v is the speed of the wave

f is the frequency

$\lambda$ is the wavelength

For the pulse in this problem,

$\lambda = 1.0 mm = 0.001 m\\v = 1400 m/s$

Solving for f, we find the frequency:

$f=\frac{v}{\lambda}=\frac{1400}{0.001}=1.4\cdot 10^6 Hz$

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2 years ago

A car traveling at a velocity v can stop in a minimum distance d. What would be the car's minimum stopping distance if it were t

alexira [117]

Answer:

a. 4d.

If the car travels at a velocity of 2v, the minimum stopping distance will be 4d.

Explanation:

Hi there!

The equations of distance and velocity of the car are the following:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position of the car at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

v = velocity of the car at time t.

Let´s find the time it takes the car to stop using the equation of velocity. When the car stops, its velocity is zero. Then:

velocity = v0 + a · t v0 = v

0 = v + a · t

Solving for t:

-v/a = t

Since the acceleration is negative because the car is stopping:

v/a = t

Now replacing t = v/a in the equation of position:

x = x0 + v0 · t + 1/2 · a · t² (let´s consider x0 = 0)

x = v · (v/a) + 1/2 · (-a) (v/a)²

x = v²/a - 1/2 · v²/a

x = 1/2 v²/a

At a velocity of v, the stopping distance is 1/2 v²/a = d

Now, let´s do the same calculations with an initial velocity v0 = 2v:

Using the equation of velocity:

velocity = v0 + a · t

0 = 2v - a · t

-2v/-a = t

t = 2v/a

Replacing in the equation of position:

x1 = x0 + v0 · t + 1/2 · a · t²

x1 = 2v · (2v/a) + 1/2 · (-a) · (2v/a)²

x1 = 4v²/a - 2v²/a

x1 = 2v²/a

x1 = 4(1/2 v²/a)

x1 = 4x

x1 = 4d

If the car travels at a velocity 2v, the minimum stopping distance will be 4d.

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2 years ago

Stacy measures two quantities: the mass of each washer and the force that the washers exert on the force meter. In general, how

geniusboy [140]

Answer:

When she adds more washers to the meter, the magnitude of force that is shown on the force meter increases.

Explanation:

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F = W = mg

Where g is gravitational acceleration and its value is 9.81 m/s² and m is the mass of any object. As she adds more washers to the meter so the total mass of the washers increases. As the mass of the washers increases, magnitude of the force (Weight) shown on the force meter increases.

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2 years ago

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Aleks [24]

Answer:

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Explanation:

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