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Fofino [41]
2 years ago
7

What is the percent composition of Ca(OH)2? 37.7% Ca, 53.0% O, and 10.3% H 45.5% Ca, 38.2% O, and 16.3% H 54.0% Ca, 43.0% O, and

2.7% H 64.7% Ca, 27.0% O, and 8.3% H
Chemistry
1 answer:
Naddik [55]2 years ago
6 0

The molar mass of Calcium hydroxide is 74 g/mol

To find the percent composition we have to find the number of atoms of each element in the formula .

So there’s

Calcium - 1

Oxygen - 2

Hydrogen - 2

Then have to multiply the relative atomic mass of each element by the number of atoms

Ca - 40 g/mol x 1 = 40

O - 16 g/mol x 2 = 32

H - 1 g/mol x 2 = 2

Then To find percent composition of each element we have to divide the mass of each element in the formula by the relative molecular mass of calcium hydroxide

Ca - 40 / 74 x 100 % = 54.0%

O - 32 / 74 x 100 % = 43.2 %

H - 2 / 74 x 100 % = 2.7%

From the options given correct answer is 3rd option

54.0% Ca , 43.0% O and 2.7 % H

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A gas occupies 2.22 l at 3.67 atm. what is the volume at 1.94 atm?
Iteru [2.4K]
According to Boyle's law, volume is inversely proportional to pressure. thus P=k/V
Therefore PV=k
P1V1=P2V2
In the question above,
P1=3.67atm
P2=1.94atm
V1=2.22L
V2=?
Thus substituting for the values in the gas equation;
3.67atm*2.22L=1.94atm*V2
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8 0
2 years ago
What mass of carbon dioxide (co2) can be produced from 86.17 grams of c6h14 and excess oxygen?
charle [14.2K]
2C6H14 + 13O2 ---> 6CO2 +14H2O

M(C6H14)=12.011*6 +1.008*14 ≈ 86.17 g/mol

86.17 g C6H14 is 1 mole.

                             2C6H14 + 13O2 ---> 6CO2 +14H2O
from reaction        2 mol                         6 mol
from the problem  1 mol                         3 mol

M(CO2)= 12.011 + 2*15.999= 44.009 g/mol
3 mol CO2*44.009 g/1 mol CO2 ≈ 132.0 g CO2
Answer : 132.0 g CO2


3 0
2 years ago
What is the buoyant force of a dog that displaces 10 pounds of water?
Troyanec [42]

Answer:

pls answer this link for the answer :D

Explanation:

brainly.com/question/22200936

5 0
2 years ago
Vinegar is an aqueous solution of acetic acid, ch3cooh. a 5.00 ml sample of a particular vinegar requires 26.90 ml of 0.175 m na
Fed [463]

  The molarity  of  acetic acid in the  vinegar is  0.94 M


 <u><em> calculation</em></u>

Step 1:  write  the balanced equation between CH3COOH  + NaOH

that is CH3COOH   + NaOH  →  CH3COONa  + H2O


step 2 :  find the moles of NaOH

moles  =molarity  x volume in L

volume in liters = 26.90/1000=0.0269 l

moles = 0.175 mol /L x 0.0269 L  =0.0047  moles  of NaOH


Step 3: use the mole  ratio to find moles of CH3COOH

that is the  mole ratio of  CH3COOH: NaOH is 1:1 therefore  the moles of CH3COOH is  =0.0047  moles


Step 4:  find the  molarity  of  CH3COOH

molarity = moles/volume in liters

volume in liter = 5.00/1000 =0.005 l

molarity  is therefore=0.0047 moles/ 0.005 l = 0.94 M

4 0
2 years ago
Hydrazine (N2H4) and dinitrogen tetroxide (N2O4) form a self-igniting mixture that has been used as a rocket propellant. The rea
Alexxx [7]

Answer:

Explanation:

An oxidizing accepts an electron and becomes reduced while a reducing agent loses an electron and become oxidized.

Chemical equation:

1) 2 N₂H₄ + N₂O₄ → 3 N₂ + 4 H₂O

2) Hydrazine ( N₂H₄)  is being oxidized

Dinitrogen tetroxide N₂O₄ is being reduced

3) The reducing agent is Hydrazine ( N₂H₄) and the oxidizing agent is dinitrogen tetroxide (N₂O₄)

5 0
2 years ago
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