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34kurt
2 years ago
12

Which part of a sandwich is most like a homogeneous mixture?

Physics
2 answers:
hoa [83]2 years ago
6 0

Bread is considered to be a heterogeneous mixture. It is a heterogeneous mixture because all of the components that are used to make the bread are physically separate.

7nadin3 [17]2 years ago
3 0

It would be B bread because bread has yest that makes it rise

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An object is thrown horizontally off a cliff with an initial velocity of 5.0 meters per second. the object strikes the ground 3
shutvik [7]
Speed is not a vector so horizontal speed does not sighify anything. If u meant velocity it vill be same as the initial velocity in horizontal direction
7 0
2 years ago
Read 2 more answers
A roller coaster accelerates from initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds . what is the acceler
Gre4nikov [31]
A roller coaster accelerates from an initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. whats the acceleration
4 0
2 years ago
A strip 1.2 mm wide is moving at a speed of 25 cm/s through a uniform magnetic field of 5.6 t. what is the maximum hall voltage
Alex787 [66]
The equation for Hall voltage Vh is:

Vh=v*B*w, where v is the velocity of the strip, B is the magnitude of the magnetic field, and w is the width of the strip. 

v=25 cm/s = 0.25 m/s
B=5.6 T
w= 1.2 mm = 0.0012 m

We input the numbers into the equation and get:

Vh= 0.25*5.6*0.0012 = 0.00168 V

The maximum Hall voltage is Vh= 0.00168 V.
4 0
2 years ago
The study of alternating electric current requires the solutions of equations of the form i equals Upper I Subscript max Baselin
KiRa [710]

Answer:

Explanation:

i = Imax sin2πft

given i = 180 , Imax = 200 , f = 50  , t = ?

Put the give values in the equation above

180 = 200 sin 2πft

sin 2πft = .9

sin2π x 50t = .9

sin 360 x 50 t = sin ( 360n + 64 )

360 x 50 t = 360n + 64

360 x 50 t =  64 ,  ( putting n = 0 for least value of t )

18000 t = 64

t = 3.55 ms  .

8 0
2 years ago
An inline skater skates on a circular track 120.0 m in diameter at a tangential speed of 9.20 m/s. If the skater’s mass is 68.5
jok3333 [9.3K]

Answer:

The centripetal force acting on the skater is <u>48.32 N.</u>

Explanation:

Given:

Radius of circular track is, R=120.0\ m

Tangential speed of the skater is, v=9.20\ m/s

Mass of the skater is, m=68.5\ kg

We are asked to find the centripetal force acting on the skater.

We know that, when an object is under circular motion, the force acting on the object is directly proportional to the mass and square of tangential speed and inversely proportional to the radius of the circular path. This force is called centripetal force.

Centripetal force acting on the skater is given as:

F_c=\frac{mv^2}{R}

Now, plug in the given values of the known quantities and solve for centripetal force, F_c. This gives,

F_c=\frac{68.5\times (9.20)^2}{120.0}\\\\F_c=\frac{68.5\times 84.64}{120}\\\\F_c=\frac{5797.84}{120}\\\\F_c=48.32\ N

Therefore, the centripetal force acting on the skater is 48.32 N.

3 0
2 years ago
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