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Delvig [45]
2 years ago
4

A shipment of shark meat was destroyed after it was found to contain 1.76 PPM methyl Mercury Which is higher than the legal limi

t of 1.00 ppm
a.if the shark meat had a mass of 12.5 kg what mass of methyl mercury was percent in the shark meat

b.what is the maximum number of grams of methyl mercury the shark meat could contain and still be considered safe to consume according to the legal limit ​
Chemistry
1 answer:
V125BC [204]2 years ago
3 0

A. The Amount of Methyl Mercury in Shark Meet:

ppm= \frac{1mg}{1kg}

Amount of Mercury: 12.5kg * \frac{1.76mg}{1kg} = 22 \ mg

B. Allowed Mass of Methyl Mercury in Shark Meet

Allowed Amount: 12.5kg * \frac{1.00mg}{1kg} = 12.5 \ mg

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Pure platinum is too soft to be used in jewelry because it scratches easily. To increase the hardness so that it can be used in
Zina [86]

Answer:

percentage mass of platinum in the alloy ≈ 90.60 %

Explanation:

The alloy is 8.528 g sample of an alloy containing platinum and cobalt . The alloy react with excess nitric acid to form cobalt(ii) nitrate . Platinum is resistant to acid so it will definitely not react with the acid only the cobalt metal in the alloy will react with the acid.

The chemical reaction can be represented as follows:

Co (s) + HNO₃ (aq) → Co(NO₃)₂ (aq) +  NO₂ (l) + H₂O (l)

The balanced equation

Co (s) + 4HNO₃ (aq) → Co(NO₃)₂(aq) + 2NO₂ (l) + 2H₂O (l)

Cobalt is the limiting reactant

atomic mass of cobalt = 58.933 g/mol

Molar mass of Co(NO₃)₂ = 58.933 + 14 × 2 + 16 × 6 = 58.933 + 28 + 96 = 182.933  g

58.933 g of cobalt produce 182.933  g of  Co(NO₃)₂

? gram of cobalt will produce 2.49 g of Co(NO₃)₂

cross multiply

grams of cobalt that will react = (58.933 × 2.49)/182.933

grams of cobalt that will react = 146.74317000/182.933

grams of cobalt that will react= 0.8021689362 g

grams of cobalt that will react = 0.802 g

mass of platinum in the alloy  = 8.528 g - 0.802 g = 7.726 g

percentage  mass of platinum in the alloy = 7.726/8.528 × 100 = 772.600/8.528 = 90 .595 %

percentage mass of platinum in the alloy ≈ 90.60 %

6 0
2 years ago
Calculate the amount of work done against an atmospheric pressure of 1.00 atm when 500.0 g of zinc dissolves in excess acid at 3
ZanzabumX [31]

Answer:

19,26 kJ

Explanation:

The work done when a gas expand with a constant atmospheric pressure is:

W = PΔV

Where P is pressure and ΔV is the change in volume of gas.

Assuming the initial volume is 0, the reaction of 500g of Zn with H⁺ (Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)) produce:

500,0g Zn(s)×\frac{1molZn}{65,38g}×\frac{1molH_{2}(g)}{1molZn} = 7,648 moles of H₂

At 1,00atm and 303,15K (30°C), the volume of these moles of gas is:

V = nRT/P

V = 7,648mol×0,082atmL/molK×303,15K / 1,00atm

V = 190,1L

That means that ΔV is:

190,1L - 0L = <em>190,1L</em>

And the work done is:

W = 1atm×190,1L = 190,1atmL.

In joules:

190,1 atmL×\frac{101,325}{1atmL} = <em>19,26 kJ</em>

I hope it helps!

5 0
2 years ago
Which statement best describes what happens when oil and water are stirred together? (1 point)
Charra [1.4K]

When oil and water are stirred together, water molecules will attract each other electrically, but they will not attract oil molecules, causing separation.

  • Water is a polar molecule while oil is a non-polar molecule. Water can only dissolve polar molecules and hence, oil is insoluble in water.

  • When water comes in contact with oil, water molecules attract each other, while the oil molecules stick together, hence, forming two separate layers of water and oil. The oil layer floats on the water layer.

  • Therefore, when oil and water are stirred together, water molecules will attract each other electrically, but they will not attract oil molecules, causing separation.

Learn more: brainly.com/question/7484286?referrer=searchResults

4 0
1 year ago
Read 2 more answers
A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equation to d
Nataly_w [17]

Answer: 91.73g of NaCl

Explanation:

First, we solve for the number of moles of F2 using the ideal gas equation

V = 12L

P = 1.5 atm

T = 280K

R = 0.082atm.L/mol/K

n =?

PV = nRT

n = PV /RT

n = (1.5x12)/(0.082x280)

n = 0.784mol

Next, we convert this mole ( i.e 0.784mol) of F2 to mass

MM of F2 = 19x2 = 38g/mol

Mass conc of F2 = n x MM

= 0.784 x 38 = 29.792g

Equation for the reaction is given below

F2 + 2NaCl —> 2NaF + Cl2

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass conc. of NaCl from the equation = 2 x 58.5 = 117g

Next, we find the mass of NaCl that reacted with 29.792g of F2.

From the equation,

38g of F2 redacted with 117g of NaCl.

Therefore, 29.792g of F2 will react with Xg of NaCl i.e

Xg of NaCl = (29.792 x 117)/38

= 91.73g

Therefore, 91.73g of NaCl reacted with f2

3 0
2 years ago
The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl et
Molodets [167]

Answer:

Explanation:

The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is aspirin. Calculate the vapor pressure of the solution at 25 °C when 14.88 grams of aspirin, C9H8O4 (180.1 g/mol), are dissolved in 269.2 grams of diethyl ether. diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol.

mol of C4H10O = mass of C4H10O / molar mass of C4H10O

= 242.1 g / 74.12 g/mol

= 3.266 mol

mol of C9H8O4 = mass of C9H8O4 / molar mass of C9H8O4

= 10.33 g / 180.1 g/mol

= 0.05736 mol

mole fraction of C4H10O,

X = mole of CHH1O0 / total mol

= (3.266)/(3.266 + 0.05736)

= 0.9827

now use:

P = Po*X

P = 463.57 * 0.9827

= 455.6 mm Hg

3 0
2 years ago
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