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irga5000 [103]
1 year ago
11

You are testing a claim that the standard deviation of time all women spend washing their hair in the morning is 15 seconds. You

find the initial conclusion of your test fails to reject the null hypothesis. State the final conclusion.
There is sufficient evidence to support the claim that the standard deviation of time all women spend washing their hair in the morning is not 15 seconds.


There is not sufficient evidence to support the claim that the standard deviation of time all women spend washing their hair in the morning is not 15 seconds.


There is sufficient evidence to support the claim that the standard deviation of time all women spend washing their hair in the morning is 15 seconds.


There is not sufficient evidence to support the claim that the standard deviation of time all women spend washing their hair in the morning is 15 seconds.
Mathematics
1 answer:
dedylja [7]1 year ago
8 0

Answer:

There is sufficient evidence to support the claim that the standard deviation of time all women spend washing their hair in the morning is 15 seconds

Step-by-step explanation:

We shall need to formulate the hypotheses but first we need to understand the claim in context of this question. The claim is that  the standard deviation of time all women spend washing their hair in the morning is 15 seconds. In mathematical notation, this claim can be written as follows;

σ = 15

Clearly the claim contains an equality sign and thus it qualifies to be our null hypothesis;

H0: σ = 15

The complement of the above hypothesis will be our alternative hypothesis;

Ha: σ ≠ 15

We are then informed that the initial conclusion of the test fails to reject the null hypothesis. In short this implies that we fail to reject the claim that the standard deviation of time all women spend washing their hair in the morning is 15 seconds since this claim is our null hypothesis. If we fail to reject a claim in hypothesis testing, this implies that there is sufficient evidence to support the claim. Therefore, there is sufficient evidence to support the claim that the standard deviation of time all women spend washing their hair in the morning is 15 seconds

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Sladkaya [172]
If he bikes for 10 miles per hour and 8 miles per hour for the same distance x miles, he went 10 miles per hour for x/10 hours, as Distance = Rate*Time and on the way back he would go for x/8 hours. So then he went 2x distance, in x/8 + x/10 hours. Since x/8 + x/10 = 10x/80 + 8x/80 = 18x/80 = 9x/40, he went 2x miles in 9x/40 hours. this can be converted into a rate with the above equation Distance = Rate*Time, so 2x=(9x/40) * Rate, thus we divide by 9x/40 on both sides to get 80x/9x = Rate, the x cancels out, and we get 80/9 Miles per hour.
4 0
2 years ago
Which rational number is one tick mark to the right of Negative 6 Over 4 on the number line below?
murzikaleks [220]

Answer:

The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).

Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:

-6/4 + 1/4 = -5/4.

Now i will give some other examples:

Now, if the distance between ticks is 2/4, then the number at the right will be:

-6/4 + 2/4 = -4/4 = -1

Now, if the distance between ticks is 3/4, the the number at the right will be:

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4 0
1 year ago
On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0
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3 litters were born at broadway kennel last year and each litter had 7 puppies how many puppies were born at broadway kennel las
frez [133]
3*7=21
21 puppies were born last year.
6 0
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A daycare center charges a $75 enrollment fee plus $100 per week. Which of the following represents the cost of sending a child
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Answer:

$1,475

Step-by-step explanation:

times 100 by 14 which is 1400

but then add 75 onto that

3 0
2 years ago
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