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BigorU [14]
2 years ago
11

Valence bond theory predicts that bromine will use _____ hybrid orbitals in brf5.

Chemistry
1 answer:
koban [17]2 years ago
5 0

Answer:

the correct answer is (sp3d2) (d)

Explanation:

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Explain why the actual electron configurations of 2-7-1-1 represents a sodium in an excited state
andre [41]
The second shell is left at 7, it should be filled to 8 to go to the next shell.
8 0
2 years ago
Rank the following amine derivatives from highest acidity (lowest pKa value) to lowest acidity (highest pKa value).
stira [4]

Answer:

anilinium ion > ammonium ion > amide > aniline > secondary amine

Explanation:

Acidity of amine derivatives can derived from their pKa values.

The rule of thumb for acidity with relation to pKa values is that:

As the pKa decreases the acid strength increases and the conjugate base decreases. Similarly, as the pKa increases, the acid strength decreases and the conjugate base increase.

Hence the stronger the acid , the  lower pKa value  and the weaker the acid , the stronger the pKa value.

So the pKa value for anilinium ion = 4.6

ammonium ion = 9.4

Amide = 15

Similarly, for aniline and secondary amine, in order to determine the derivative with the higher acidity, we will consider the electron withdrawing substituent group.

The more difficult the electron are being withdraw from the electron withdrawing substituent , the more acidic the compound.

In aniline , the stabilized benzene ring attached to NH₂ makes it a less electron withdrawing group compared to the straight chains structure found in secondary amine where electron are easily withdraw by nucleophilic substitution reactions.

Thus, from highest acidity (lowest pKa value) to lowest acidity (highest pKa value).

the amine derivatives ranking is as follows:

anilinium ion > ammonium ion > amide > aniline > secondary amine

8 0
2 years ago
1. Concentrated HCl is 11.7M. What is the
SSSSS [86.1K]

Answer:

The concentration is 0,2925M

Explanation:

We use the formula

C initial  x V initial = C final x V final

11,7 M x 25 ml = C final x 1000 ml

C final= (11,7 M x 25 ml)/1000 ml = 0, 2925 M

(This formula applies to liquid solutions)

6 0
2 years ago
Which compound forms a green aqueous solution
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NiCl₂ commonly forms a green aqueous solution.
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a mixture was found to contain 1.05g of sio2, 0.69g of cellulose, and 1.82g of calcium carbonate, what percentage of calcium car
enot [183]
Mass percentage is another way of expressing concentration of a substance in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100%. It is calculated as follows:

% CaCO3 = (<span>1.82g of calcium carbonate</span> / (1.05 g SiO2 + 0.69 g of cellulose + <span>1.82g of calcium carbonate)) x 100% = 51.12% Calcium carbonate</span>
6 0
1 year ago
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