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2 years ago

Write a balanced equation for the reaction of NaCH3COO (also written as NaC2H3O2) and HCl

2 answers:

6 0

The chemical reaction of the reactants, NaCH3COO and HCl, is written as follows:

NaCh3COO + HCl = NaCl + CH3COOH

To balance it, the number of atoms of an element in one side should be equal to the other side. By looking at the reaction, I believe it is already balanced. They have 1 is to 1 ratios.

mariarad [96]2 years ago

6 0

Answer:

$CH_3COONa~+~HCl~->~CH_3COOH~+~NaCl$

Explanation:

This is an acid-base reaction in which the HCl is the acid and the $CH_3COONa$ is the base.

In the balanced reaction, we will have a double replacement reaction. In which the cation of $CH_3COONa$ (in this case $Na^+$ ) will be exchanged by the hydronium ion $H^+$ from the $HCl$ . Similarly the anion of $HCl$ ( $Cl^-$ ) would bond with the cation $Na^+$ to form $NaCl$ .

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3 ways of improving the quality of an indigenous soap

Monica [59]

Answer : Below are three ways described in brief for improving the quality of indigenous soap.

1) Add virgin coconut oil which serves as a softener and betel leaf extract. It is used to improve the quality of soap as an antimicrobial agent.

2) Add activated charcoal black granules or powder to the soap, it removes maximum dirt from the skin.

3) Adding a filler which will increase the shelf life of usage of the soap will also improve its quality.

4 0

2 years ago

In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)

Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 3.6 L

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm (From correct source)

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}$

${V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L$

${V_2}=0.27\ L$

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

7 0

2 years ago

To find the Ce4+ content in a solid sample, 4.3718 g of the solid sample were dissolved and treated with excess iodate to precip

gulaghasi [49]

Answer:

3.43 %

Explanation:

We need to calculate first the number of moles of CeO2 produced in the combustion. Given its formula we know how many moles of Ce atom are present. From there calculate the mass this number of moles this represent and then one can calculate the percentage.

0.1848 g CeO2 x 1 mol CeO2/172.114g = 0.00107 mol CeO2

0.00107 mol CeO2 x 1 mol Ce/ 1 mol CeO2 = 0.00107 mol Ce

.00107 mol Ce x 140.116 g Ce/ mol = 0.150 g Ce

0.150 g Ce/ 4.3718 g sample x 100 = 3.43 %

5 0

2 years ago

Read 2 more answers

Using the data, which of the following is the rate constant for the rearrangement of methyl isonitrile at 320 ∘C? (HINT: the act

svp [43]

Explanation:

Below is an attachment containing the solution.