Answer is: A. Chemical energy to electromagnetic energy and thermal energy.
Balanced chemical reaction: 2Mg(s) + O₂(g) → 2MgO(s) + energy.
This is chemical change (chemical reaction), because new substance (magnesium oxide MgO) is formed, the atoms are rearranged and the reaction is followed by an energy change (exothermic reaction because energy is released).
Chemical changes (chemical synthesis) is when a substance combines with another (in this example magnesium and oxygen) to form a new substance.
Answer:
The partial pressure of carbon dioxide is 22.8 mmHg
Explanation:
Dalton's Law is a gas law that relates the partial pressures of the gases in a mixture. This law says that the pressure of a gas mixture is equal to the sum of the partial pressures of all the gases present.
In this case:
Ptotal=Pnitrogen + Poxygen + Pcarbondioxide
You know that:
- Ptotal= 0.998 atm
- Pnitrogen= 0.770 atm
- Poxygen= 0.198 atm
- Pcarbondioxide= ?
Replacing:
0.998 atm=0.770 atm + 0.198 atm + Pcarbondioxide
Solving:
Pcarbondioxide= 0.998 atm - 0.770 atm - 0.198 atm
Pcarbondioxide= 0.03 atm
Now you apply the following rule of three: if 1 atm equals 760 mmHg, 0.03 atm how many mmHg equals?

Pcarbondioxide= 22.8 mmHg
<u><em>The partial pressure of carbon dioxide is 22.8 mmHg</em></u>
Answer:
Ethynylcyclopropane is the stable isomer for given alkyne.
Explanation:
In order to solve this problem we will first calculate the number of Hydrogen atoms. The general formula for alkynes is as,
CₙH₂ₙ₋₂
Putting value on n = 5,
C₅H₂.₅₋₂
C₅H₈
Also, the statement states that the compound contains one ring therefore, we will subtract 2 hydrogen atoms from the above formula i.e.
C₅H₈ ------------(-2 H) ----------> C₅H₆
Hence, the molecular formula for given compound is C₅H₆
Below, 4 different isomers with molecular formula C₅H₆ are attached.
The first compound i.e. ethynylcyclopropane is stable. As we know that alkynes are sp hybridized. The angle between C-C-H in alkynes is 180°. Hence, in this structure it can be seen that the alkyne part is linear and also the cyclopropane part is a well known moiety.
Compounds 3-ethylcycloprop-1-yne, <u>cyclopentyne </u>and 3-methylcyclobut-1-yne are highly unstable. The main reason for the instability is the presence of triple bond in three, five and four membered ring. As the alkynes are linear but the C-C-H bond in these compound is less than 180° which will make them highly unstable.
Answer: Reaction 1 is non spontaneous.
Explanation:
According to Gibb's equation:

= Gibbs free energy
= enthalpy change
= entropy change
T = temperature in Kelvin
When
= +ve, reaction is non spontaneous
= -ve, reaction is spontaneous
= 0, reaction is in equilibrium
For the given reaction 1:

As for the reaction 1 , the value of Gibbs free energy is positive and thus the reaction 1 is non spontaneous.