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erma4kov [3.2K]
2 years ago
12

The potential energy diagram shows the gain and loss of potential energy as water molecules decompose into hydrogen and oxygen.

Label the parts of the diagram

Chemistry
1 answer:
Dovator [93]2 years ago
4 0

Answer:

  • The<em> diagram</em> with the five<em> labels</em> of the parts is in the image attached. Please, see the image.

Explanation:

<u>1) General explanation:</u> a <em>potential chemical energy diagram</em> is used to show how the <em>reactants</em> gain energy until they reach the <em>activation energy</em>, form the <em>activated complex</em>, and release part of the energy to form the <em>products</em>.

The difference between the chemical potential energy of the products and the reactants is the <em>enthalpy of the reaction</em>:

  • ΔH rxn = ΔH products - ΔH reactants.

The labels that correspond to each part of the diagram are explained next.

<em><u>2) Reactants:</u></em>

This is the substances at the start, so they appear on the left bottom side of the diagram.

<em><u>3) Activation energy:</u></em>

It is the energy that the reactants must reach (the highest point) in order to the reaction occurs.

<u><em>4) Activated complex:</em></u>

This is the intermediate state and of highest energy. The reactants have formed a complex at mid way between the reactants and the products.

<u><em>5) Products:</em></u>

These are the substances formed when the reaction is completed. They are lower in energy than the activated complex. They can be either higher or lower in energy than the reactants. The products are shown to the right of the diagram.

<em><u>6) Enthalpy of the reaction:</u></em>

The enthalpy of the reaction is the difference in energy of the products and the reactants. In this case, since, the products are higher in energy, it means that the reaction absorbed energy and it is an endothermic reaction.

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The answer is <span>D.when the aim is to show electron distributions in shells. This is because there are some instances when elements don't possess a regular or normal electron configuration. There are those who have special electron configurations wherein a lower subshell isn't completely filled before occupying a higher subshell. It is best to visualize such cases using the orbital notation.</span>
8 0
2 years ago
A filament of a light bulb is made from a pure sample of tungsten.
GenaCL600 [577]

Answer:

The correct options are:

1) Pure chemical substance

2) Element.

Explanation:

each of the term is explained below:

1) <u>Mixture: </u> Since tungsten is an element in periodic table thus it is not a mixture.

2) False by definition of mixture.

3) false by definition of mixture.

4) <u>Solution:</u> Tungsten in a filament is in solid form hence solution is incorrect.

5) Since it is given in the question itself that the sample is pure hence option 'E' is correct as chemical substance is a pure substance that has a homogeneous composition and the sample in the question is given as pure.

6) <u>Compound:</u> By definition of compound it is formed by mixing 2 or more elements but since tungsten is an element that occurs independently in nature hence it is not a compound.

7) Tungsten is a element in the periodic table with atomic number 74.

8 0
2 years ago
A generic gas, x, is placed in a sealed glass jar and decomposes to form gaseous y and solid z. 2x(g)↽−−⇀y(g)+z(s) how are these
Aleksandr [31]
Answer: the equilibrium will be displaced to the right leading an increase on the quantities of y(g) and z(s).

Justification:

According to the rules of equilibrium, based on Le Chatellier's priciple, any change in a system in equilibrium will be tried to be compensated to restablish the equilibrium

The higher the amount, and so the concentration, of X(g), the more will the forward reaction proceed leading to an increase on the concentration of the products y(g) and z (s). Look that that will also be accompanied by a decreasing on the pressure, since 2 molecules of the gas X(g) are converted into 1 molecule of the gas y(g).
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2 years ago
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How many molecules of glucose are in 1 l of a 100 mm glucose solution?
Karolina [17]

Answer is: 6.022·10²² molecules of glucose.

c(glucose) = 100 mM.

c(glucose) = 100 · 10⁻³ mol/L.

c(glucose) = 0.1 mol/L; concentration of glucose solution.

V(glucose) = 1 L; volume of glucose solution.

n(glucose) = c(glucose) · V(glucose).

n(glucose) = 0.1 mol/L · 1 L.

n(glucose) = 0.1 mol; amount of substance.

N(glucose) = n(glucose) · Na (Avogadro constant).

N(glucose) = 0.1 mol · 6.022·10²³ 1/mol.

N(glucose) = 6.022·10²².

6 0
2 years ago
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Greeley [361]
First, we must find the total mass of CuBr₂:
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Percentage mass of copper = mass of copper x 100 / total mass
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